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<h1>Comparison of some optimal derivative–free three–point iterations</h1>
<p class="authors">
<span class="author">Thugal Zhanlav\(^\bullet \) Khuder Otgondorj\(^{\bullet ,\ast }\)</span>
</p>
<p class="date">March 14, 2019; accepted: March 4 2020; published online: August 11, 2020.</p>
</div>
<div class="abstract"><p> We show that the well-known Khattri <i class="itshape">e</i>t al. <span class="cite">
	[
	
	<a href="#4" >5</a>
	
	]
</span> methods and Zheng <i class="itshape">e</i>t al. <span class="cite">
	[
	
	<a href="#9" >14</a>
	
	]
</span> methods are identical. In passing we propose suitable calculation formula for Khattri <i class="itshape">e</i>t al. methods. We also show that the families of eighth-order derivative-free methods obtained in <span class="cite">
	[
	
	<a href="#8" >13</a>
	
	]
</span> include some existing methods, among them the above mentioned ones as particular cases. We also give the sufficient convergence condition of these families. Numerical examples and comparison with some existing methods were made. In addition, the dynamical behavior of methods of these families is analyzed. </p>
<p><b class="bf">MSC.</b> 65H05. </p>
<p><b class="bf">Keywords.</b> Nonlinear equations, Derivative-free methods, Optimal three point iterative methods. </p>
</div>
<p>\(^\bullet \)Institute of Mathematics and Digital Technology, Mongolian Academy of Sciences, Mongolia e-mail: <span class="tt">tzhanlav@yahoo.com</span>. </p>
<p>\(^\ast \)School of Applied Sciences, Mongolian University of Science and Technology, Mongolia e-mail: <span class="tt">otgondorj@gmail.com</span>. </p>
<h1 id="sec1">1 Introduction</h1>

<p>At present there exist many optimal derivative-free three-point iterations see, for example, <span class="cite">
	[
	
	<a href="#1" >1</a>
	-
	<a href="#3" >3</a>
	, 
	<a href="#4" >5</a>
	-
	<a href="#7" >9</a>
	-
</span> and references therein. They mainly distinguished among themselves by approximations of \(f'(z_n)\) at the last step. Let the values of \(f(x)\) be known at points \(x_n\), \(w_n\), \(y_n\) and \(z_n\). Often the following three approaches are used for approximation \(f'(z_n)\). The most preferred approximation (see <span class="cite">
	[
	
	<a href="#1" >1</a>
	
	]
</span>,<span class="cite">
	[
	
	<a href="#5" >6</a>
	, 
	<a href="#6" >7</a>
	, 
	<a href="#7" >9</a>
	
	]
</span>,<span class="cite">
	[
	
	<a href="#9" >14</a>
	
	]
</span>) is </p>
<div class="displaymath" id="1.2">
  \begin{eqnarray} \label{1.2} f’(z_n)\approx N’_3(z_n), \end{eqnarray}
</div>
<p> where \(N_3(z)\) is Newton’s interpolation polynomial of degree three at the point \(x_n,\) \(w_n,\) \(y_n\) and \(z_n\). The second approach is <span class="cite">
	[
	
	<a href="#4" >5</a>
	
	]
</span> </p>
<div class="displaymath" id="1.3">
  \begin{eqnarray} \label{1.3} f’(z_n)\approx \nu _1 f(x_n)+\nu _2 f(w_n)+\nu _3 f(y_n)+\nu _4 f(z_n). \end{eqnarray}
</div>
<p> The real constants \(\nu _1,\) \(\nu _2,\) \(\nu _3\) and \(\nu _4\) are determined such that the relation (<a href="#1.3">2</a>) holds with equality for the four functions \(f(x)=1\), \(x\), \(x^2\), \(x^3.\) While in <span class="cite">
	[
	
	<a href="#8" >13</a>
	
	]
</span> was used the approximation </p>
<div class="displaymath" id="1.4">
  \begin{eqnarray} \label{1.4} & &  f’(z_n)\approx a f(x_n)+b f(y_n)+c f(z_n)+d \phi (x_n),\nonumber \\ & & \phi (x_n)=\tfrac {f(w_n)-f(x_n)}{w_n-x_n}=f[x_n,w_n]. \end{eqnarray}
</div>
<p> The real constants \(a, b, c\) and \(d\) in (<a href="#1.4">3</a>) are determined such that the equality (<a href="#1.4">3</a>) holds with accuracy \(\mathcal{O}(f(x_n)^4).\) Note that in last years have been appeared papers, in which were used another approximations such as Pade approximant <span class="cite">
	[
	
	<a href="#3" >3</a>
	
	]
</span> and rational approximations <span class="cite">
	[
	
	<a href="#2" >2</a>
	
	]
</span> and so on. As we seen from (<a href="#1.2">1</a>), (<a href="#1.3">2</a>) and (<a href="#1.4">3</a>) more suitable and guaranteed approximation is (<a href="#1.4">3</a>). In general, all these three approaches turn out to be identical. This is well-known long ago fact <span class="cite">
	[
	
	<a href="#11" >16</a>
	
	]
</span>. This idea motivated us to make detail comparison of methods based on (<a href="#1.2">1</a>), (<a href="#1.3">2</a>) and (<a href="#1.4">3</a>). Note that the detail comparison of optimal three-point methods was made in <span class="cite">
	[
	
	<a href="#3'" >4</a>
	
	]
</span> and such comparison for optimal derivative-free methods is still needed. The paper organized as follows. In <a href="#sec2">section 2</a> we consider some methods based on the approximations (<a href="#1.2">1</a>), (<a href="#1.3">2</a>), (<a href="#1.4">3</a>) and made comparison of them. We obtain the sufficient convergence condition for these families in <a href="#sec3">section 3</a>. Numerical and visual comparison some optimal derivative-free methods are made in <a href="#sec4">section 4</a>. </p>
<h1 id="sec2">2 Some methods based on the approximation (<a href="#1.2">1</a>), (<a href="#1.3">2</a>) and (<a href="#1.4">3</a>)</h1>
<p> The well-known Zheng <i class="itshape">e</i>t al. <span class="cite">
	[
	
	<a href="#9" >14</a>
	
	]
</span> methods (Z8) based on (<a href="#1.2">1</a>) and has a form </p>
<div class="displaymath" id="2.6">
  \begin{eqnarray} \label{2.6} & & y_n=x_n-\tfrac {f(x_n)}{f[x_n,w_n]},\quad w_n=x_n+\gamma f(x_n),\quad \gamma \in \mathbb {R} \setminus \{ 0\}  \nonumber \\ & & z_n=y_n-\tfrac {f(y_n)}{f[x_n,y_n]+f[y_n,w_n]-f[x_n,w_n]} ,\\ & & x_{n+1}=z_n-\tfrac {f(z_n)}{f[z_n,y_n]+(z_n-y_n)f[z_n,y_n,x_n]+(z_n-y_n)F}\nonumber , \end{eqnarray}
</div>
<p> where \(F=(z_n-x_n)f[z_n,y_n,x_n,w_n]\). Based on (<a href="#1.3">2</a>) the well-known Khattri <i class="itshape">e</i>t al. <span class="cite">
	[
	
	<a href="#4" >5</a>
	
	]
</span> methods (KS8) has the following form: </p>
<div class="displaymath" id="2.7">
  \begin{eqnarray} \label{2.7} & & y_n=x_n-\tfrac {f(x_n)}{f[x_n,w_n]}, \nonumber \\ & & z_n=y_n-\frac{f(y_n)}{\frac{x_n-y_n+\gamma f(x_n)}{(x_n-y_n)\gamma }-\frac{(x_n-y_n) f(w_n)}{(w_n-y_n)\gamma f(x_n)}-\frac{(2x_n-2y_n+\gamma f(x_n))f(y_n) }{(x_n-y_n)(w_n-y_n)}} ,\\ & & x_{n+1}=z_n-\tfrac {f(z_n)}{H_1+H_2+H_3-H_4}\nonumber . \end{eqnarray}
</div>
<p> Here </p>
<div class="displaymath" id="2.8">
  \begin{eqnarray} \label{2.8} & & H_1=-\tfrac {(y_n-z_n)(w_n-z_n) }{(x_n-z_n)\gamma (x_n-y_n)},\nonumber \\ & & H_2=\tfrac {(y_n-z_n)(x_n-z_n)f(w_n) }{(w_n-z_n)(w_n-y_n)\gamma f(x_n)},\\ & & H_3=\tfrac {(x_n-z_n)(w_n-z_n)f(y_n)}{(y_n-z_n)(w_n-y_n)(x_n-y_n)},\nonumber \\ & & H_4=\tfrac {\gamma (x_n-2z_n+y_n)f(x_n)+x_n^2+(-4z_n+2y_n)x_n+3z_n^2-2y_nz_n }{(y_n-z_n)(x_n-z_n)(w_n-z_n)}f(z_n).\nonumber \end{eqnarray}
</div>
<p> In <span class="cite">
	[
	
	<a href="#4" >5</a>
	
	]
</span>, the authors pointed out that these methods given by (<a href="#2.7">5</a>), (<a href="#2.8">6</a>) is similar to the already known methods proposed in <span class="cite">
	[
	
	<a href="#1" >1</a>
	, 
	<a href="#5" >6</a>
	, 
	<a href="#6" >7</a>
	, 
	<a href="#7" >9</a>
	
	]
</span>, in particular to method in <span class="cite">
	[
	
	<a href="#9" >14</a>
	
	]
</span>, however, they are not the same methods. From (<a href="#2.6">4</a>) and (<a href="#2.7">5</a>) we see that the second and third substeps in (<a href="#2.7">5</a>) are much complicated as compared with (<a href="#2.6">4</a>). The formula, requiring many mathematical operations absolutely unfitted for numerical and stability points of view. Hence, the formula (<a href="#2.7">5</a>) needed further simplifications. The families of derivative-free optimal methods proposed in <span class="cite">
	[
	
	<a href="#8" >13</a>
	
	]
</span> are based on (<a href="#1.4">3</a>) and have a form </p>
<div class="displaymath" id="2.9">
  \begin{eqnarray} \label{2.9} & &  y_n=x_n-\tfrac {f(x_n)}{f[x_n,w_n]},\nonumber \\ & & z_n=y_n-\bar{\tau }_n\tfrac {f(y_n)}{f[x_n,w_n]},\\ & &  x_{n+1}=z_n-\alpha _n\tfrac {f(z_n)}{f[x_n,w_n]},\nonumber \end{eqnarray}
</div>
<p> where </p>
<div class="displaymath" id="2.10">
  \begin{eqnarray} \label{2.10} \bar{\tau }_n=\tfrac {c+(\hat{d}_n c+d)\theta _n+\omega \theta _n^2}{c+d\theta _n+b\theta _n^2}, \quad c+d+b\neq 0, \quad c,d,b,\omega \in \mathbb {R}. \end{eqnarray}
</div>
<p> and </p>
<div class="displaymath" id="2.11">
  \begin{eqnarray} \label{2.11} \alpha _{n}=\tfrac {1}{\Big(1+a_nw_n\bigl( \frac{f[z_n,x_n]}{f[x_n,w_n]}-1\bigr) +b_n\gamma _n\bigr( \frac{f[z_n,y_n]}{f[x_n,w_n]}-1\bigl)\Big)}, \end{eqnarray}
</div>
<p> with </p>
<div class="displaymath" id="2.12">
  \begin{eqnarray} \label{2.12} & &  a_nw_n=(1-\tau _n)\tfrac {2\tau _n+\gamma \phi _n+(\tau _n+\gamma \phi _n)^2}{(\tau _n+\gamma \phi _n)(1+\gamma \phi _n)},\nonumber \\ & &  b_n\gamma _n=\tfrac {\tau _n(\tau _n+\gamma \phi _n)}{1+\gamma \phi _n}, \quad \phi _n=f[x_n,w_n], \\ & & \tau _n=1+\bar{\tau }_n\theta _n,\quad \theta _n=\tfrac {f(y_n)}{f(x_n)}\nonumber . \end{eqnarray}
</div>
<p> We call the representation (<a href="#2.9">7</a>) of three-point methods as canonical form. Each derivative-free three-point methods, in particular the methods (<a href="#2.6">4</a>) and (<a href="#2.7">5</a>) can be written in canonical form uniquely. Note that all the considered methods (<a href="#2.6">4</a>), (<a href="#2.7">5</a>) and (<a href="#2.9">7</a>) are optimal in the sense of Kung and Traub <span class="cite">
	[
	
	<a href="#12" >17</a>
	
	]
</span>. So they has an efficiency index \(8^{1/4}\approx 1.68179 \). The methods (<a href="#2.6">4</a>) and (<a href="#2.7">5</a>) contain one free parameter \(\gamma \), whereas the methods (<a href="#2.9">7</a>) contain, in addition \(\gamma \), yet four parameter \(c\), \(d\), \(b\) and \(w\). Hence, in our opinion, the families (<a href="#2.9">7</a>) represent a wide class of optimal three-point methods. Our aim is to compare the above mentioned methods in detail. First, we will show that the optimal derivative-free methods (<a href="#2.6">4</a>) and (<a href="#2.7">5</a>) are identical. Namely, we obtain <div class="theorem_thmwrapper " id="th1">
  <div class="theorem_thmheading">
    <span class="theorem_thmcaption">
    Theorem
    </span>
    <span class="theorem_thmlabel">1</span>
  </div>
  <div class="theorem_thmcontent">
  <p> The optimal derivative-free methods <a href="#2.6" class="eqref">4</a> and <a href="#2.7" class="eqref">5</a> are equivalent. </p>

  </div>
</div> <div class="proof_wrapper" id="a0000000002">
  <div class="proof_heading">
    <span class="proof_caption">
    Proof
    </span>
    <span class="expand-proof">â–¼</span>
  </div>
  <div class="proof_content">
  
  </div>
</div> Using easily verifying relations </p>
<div class="displaymath" id="2.13">
  \begin{eqnarray} \label{2.13} f[x_n,y_n]=\phi _n(1-\theta _n),~  f[y_n,w_n]=\phi _n(1-\tfrac {\theta _n}{1+\gamma \phi _n}), \end{eqnarray}
</div>
<p> the second-step in (<a href="#2.6">4</a>) and (<a href="#2.7">5</a>) can be easily rewritten as </p>
<div class="displaymath" id="2.14">
  \begin{eqnarray} \label{2.14} z_n=y_n-\bar{\tau }_n\tfrac {f(y_n)}{f[x_n,w_n]}, \end{eqnarray}
</div>
<p> where </p>
<div class="displaymath" id="2.14'">
  \begin{eqnarray} \label{2.14'} \bar{\tau }_n=\tfrac {1}{1-\hat{d}_n\theta _n}, \quad \hat{d}_n=\tfrac {2+\gamma \phi _n}{1+\gamma \phi _n}. \end{eqnarray}
</div>
<p> Thus, the first two sub-steps of (<a href="#2.6">4</a>) and (<a href="#2.7">5</a>) are the same. In passing, we obtain very simple calculation formula (<a href="#2.14">12</a>) for iteration method (<a href="#2.7">5</a>). It remains to compare the third sub-steps in (<a href="#2.6">4</a>) and (<a href="#2.7">5</a>). The third sub-steps in (<a href="#2.6">4</a>) and (<a href="#2.7">5</a>) can be rewritten as </p>
<div class="displaymath" id="a0000000003">
  \begin{eqnarray*}  x_{n+1}=z_n-\alpha _n\tfrac {f(z_n)}{f[x_n,w_n]}, \end{eqnarray*}
</div>
<p> where </p>
<div class="displaymath" id="n14">
  \begin{eqnarray} \label{n14} & & \alpha _{n}=\tfrac {\phi _n}{f[z_n,y_n]+(z_n-y_n)f[z_n,y_n,x_n]+(z_n-y_n)F} \end{eqnarray}
</div>
<p> for iteration (<a href="#2.6">4</a>) and </p>
<div class="displaymath" id="n15">
  \begin{eqnarray} \label{n15} \alpha _{n}=\tfrac {\phi _n}{H_1+H_2+H_3-H_4}, \end{eqnarray}
</div>
<p> for iteration (<a href="#2.7">5</a>). Using the following relations </p>
<div class="displaymath" id="2.16">
  \begin{eqnarray} \label{2.16} & & f[z_n,y_n]=\tfrac {\phi _n}{\bar{\tau }_n}(1-\upsilon _n),~  \upsilon _n=\tfrac {f(z_n)}{f(y_n)},~  f[z_n,x_n]=\tfrac {\phi _n}{\tau _n}(1-\theta _n\upsilon _n),\nonumber \\ & & f[z_n,y_n,x_n]=\tfrac {\phi _n^2}{\tau _n f(x_n)}\tfrac {\bar{\tau }_n(1-\theta _n)-(1-\upsilon _n)}{\bar{\tau }_n},\\ & & f[z_n,y_n,x_n,w_n]=\tfrac {\phi _n^3}{ f^2(x_n)(\tau _n+\gamma \phi _n)}\big(\tfrac {\theta _n}{1+\gamma \phi _n}-\tfrac {\bar{\tau }_n-\tau _n+\upsilon _n}{\bar{\tau }_n\tau _n}\big),\nonumber \end{eqnarray}
</div>
<p> one can write (<a href="#n14">14</a>) as: </p>
<div class="displaymath" id="n14'4">
  \begin{eqnarray} \label{n14'4} \alpha _{n}=\frac{1}{\frac{\tau _n(\tau _n+\gamma \phi _n)}{(\tau _n-1)(1+\gamma \phi _n)}\theta _n+(1-\tau _n)\frac{2\tau _n+\gamma \phi _n}{\tau _n(\tau _n+\gamma \phi _n)}-Q\theta _n\upsilon _n}, \end{eqnarray}
</div>
<p> where \(Q=\frac{\tau _n(3\tau _n-2)+\gamma \phi _n(2\tau _n-1)}{\tau _n(\tau _n-1)(\tau _n+\gamma \phi _n)}.\) In a similar way, using (<a href="#2.16">16</a>), the expression (<a href="#n15">15</a>) can be easily rewritten as (<a href="#n14'4">17</a>). Thus, the third-step of (<a href="#2.6">4</a>) and (<a href="#2.7">5</a>) also coincide with each other. </p>
<p>Therefore, the iterations (<a href="#2.6">4</a>) and (<a href="#2.7">5</a>) are identical. <div class="proof_wrapper" id="a0000000004">
  <div class="proof_heading">
    <span class="proof_caption">
    Proof
    </span>
    <span class="expand-proof">â–¼</span>
  </div>
  <div class="proof_content">
  
  </div>
</div> So the methods (<a href="#2.7">5</a>) can be considered as rediscovered variant of Zheng <i class="itshape">e</i>t al. <span class="cite">
	[
	
	<a href="#9" >14</a>
	
	]
</span> ones. Now, we use the relations (<a href="#2.16">16</a>) in (<a href="#2.11">9</a>). After some algebraic manipulations we again arrive at (<a href="#n14'4">17</a>). It means that the third sub-step of iterations (<a href="#2.6">4</a>) and (<a href="#2.9">7</a>) are the same. </p>
<p>Therefore, the iterations (<a href="#2.6">4</a>), (<a href="#2.7">5</a>) and (<a href="#2.9">7</a>) can be written in more convenient and unified form as: </p>
<div class="displaymath" id="2.17">
  \begin{eqnarray} \label{2.17} & & y_n=x_n-\tfrac {f(x_n)}{f[x_n,w_n]},\nonumber \\ & & z_n=y_n-\bar{\tau }_n\tfrac {f(y_n)}{f[x_n,w_n]},\\ & & x_{n+1}=z_n-\tfrac {f(z_n)}{f[z_n,y_n]+(z_n-y_n)f[z_n,y_n,x_n]+(z_n-y_n)F},\nonumber \end{eqnarray}
</div>
<p> where \(\bar{\tau }_n\) is given by (<a href="#2.10">8</a>) for (<a href="#2.9">7</a>) and is given by (<a href="#2.14'">13</a>) for (<a href="#2.6">4</a>) and (<a href="#2.7">5</a>). When \(c=1\), \(d=-\hat{d}_n\) and \(\omega =b=0\) in (<a href="#2.10">8</a>), \(\bar{\tau }_n\) coincides with (<a href="#2.14">12</a>). In this case the iterations (<a href="#2.6">4</a>) and (<a href="#2.7">5</a>) and (<a href="#2.17">18</a>) are identical. So our iterations (<a href="#2.9">7</a>) contain the methods (<a href="#2.6">4</a>) and (<a href="#2.7">5</a>) as particular cases. In addition, the iterations (<a href="#2.17">18</a>) contain some well-known iterations as particular cases (see Table <a href="#tab1">1</a>). </p>
<p>Later on, we denote the method (<a href="#2.17">18</a>) with \(c=1\), \(d=-\hat{d}_n\), \(b=-\frac{1}{1+\gamma \phi _n}\) and \(\omega =0\) by M1. These parameters are chosen to have a large region of convergence and a big basin of attraction for family <a href="#2.17" class="eqref">18</a>. </p>
<div class="table"  id="tab1">
   <div class="centered"><small class="small"> !<table class="tabular">
  <tr>
    <td  style="border-top-style:solid; border-top-color:black; border-top-width:1px; text-align:left; border-left:1px solid black" 
        rowspan=""
        colspan="">
      <p> \(c\)</p>

    </td>
    <td  style="border-top-style:solid; border-top-color:black; border-top-width:1px; text-align:center" 
        rowspan=""
        colspan="">
      <p>\(d\)</p>

    </td>
    <td  style="border-top-style:solid; border-top-color:black; border-top-width:1px; text-align:center" 
        rowspan=""
        colspan="">
      <p>\(b\)</p>

    </td>
    <td  style="border-top-style:solid; border-top-color:black; border-top-width:1px; text-align:center; border-right:1px solid black" 
        rowspan=""
        colspan="">
      <p>\(w\) </p>

    </td>
    <td  style="border-top-style:solid; border-top-color:black; border-top-width:1px; text-align:center; border-right:1px solid black" 
        rowspan=""
        colspan="">
      <p> \(\bar{\tau }_n\)</p>

    </td>
    <td  style="border-top-style:solid; border-top-color:black; border-top-width:1px; text-align:center; border-right:1px solid black" 
        rowspan=""
        colspan="">
      <p>methods </p>

    </td>
  </tr>
  <tr>
    <td  style="border-top-style:solid; border-top-color:black; border-top-width:1px; text-align:left; border-left:1px solid black" 
        rowspan=""
        colspan="">
      
<p>\(1\)</p>

    </td>
    <td  style="border-top-style:solid; border-top-color:black; border-top-width:1px; text-align:center" 
        rowspan=""
        colspan="">
      <p>\(-\hat{d}_n\) </p>

    </td>
    <td  style="border-top-style:solid; border-top-color:black; border-top-width:1px; text-align:center" 
        rowspan=""
        colspan="">
      <p> \(0\) </p>

    </td>
    <td  style="border-top-style:solid; border-top-color:black; border-top-width:1px; text-align:center; border-right:1px solid black" 
        rowspan=""
        colspan="">
      <p>\(0\)</p>

    </td>
    <td  style="border-top-style:solid; border-top-color:black; border-top-width:1px; text-align:center; border-right:1px solid black" 
        rowspan=""
        colspan="">
      <p>\(\frac{1}{1-\tilde{d}_n\theta _n}\)</p>

    </td>
    <td  style="border-top-style:solid; border-top-color:black; border-top-width:1px; text-align:center; border-right:1px solid black" 
        rowspan=""
        colspan="">
      <p>(Z8), (KS8)</p>

    </td>
  </tr>
  <tr>
    <td  style="border-top-style:solid; border-top-color:black; border-top-width:1px; text-align:left; border-left:1px solid black" 
        rowspan=""
        colspan="">
      
<p>\(1\)</p>

    </td>
    <td  style="border-top-style:solid; border-top-color:black; border-top-width:1px; text-align:center" 
        rowspan=""
        colspan="">
      <p>\(-\frac{1}{1+\gamma \phi _n}\) </p>

    </td>
    <td  style="border-top-style:solid; border-top-color:black; border-top-width:1px; text-align:center" 
        rowspan=""
        colspan="">
      <p> 0 </p>

    </td>
    <td  style="border-top-style:solid; border-top-color:black; border-top-width:1px; text-align:center; border-right:1px solid black" 
        rowspan=""
        colspan="">
      <p>\(\frac{a\hat{d}_n}{2}\)</p>

    </td>
    <td  style="border-top-style:solid; border-top-color:black; border-top-width:1px; text-align:center; border-right:1px solid black" 
        rowspan=""
        colspan="">
      <p>\(\frac{1+\theta _n+a\hat{d}_n\frac{\theta _n^2}{2}}{1-\frac{\theta _n}{1+\gamma \phi _n}}\)</p>

    </td>
    <td  style="border-top-style:solid; border-top-color:black; border-top-width:1px; text-align:center; border-right:1px solid black" 
        rowspan=""
        colspan="">
      <p>Lotfi (L8) <span class="cite">
	[
	
	<a href="#5" >6</a>
	
	]
</span></p>

    </td>
  </tr>
  <tr>
    <td  style="border-top-style:solid; border-top-color:black; border-top-width:1px; text-align:left; border-left:1px solid black" 
        rowspan=""
        colspan="">
      
<p>\(1\)</p>

    </td>
    <td  style="border-top-style:solid; border-top-color:black; border-top-width:1px; text-align:center" 
        rowspan=""
        colspan="">
      <p>\(\beta -1-\hat{d}_n\) </p>

    </td>
    <td  style="border-top-style:solid; border-top-color:black; border-top-width:1px; text-align:center" 
        rowspan=""
        colspan="">
      <p> \(\frac{2-\beta }{1+\gamma \phi _n}\) </p>

    </td>
    <td  style="border-top-style:solid; border-top-color:black; border-top-width:1px; text-align:center; border-right:1px solid black" 
        rowspan=""
        colspan="">
      <p>\(\beta \)</p>

    </td>
    <td  style="border-top-style:solid; border-top-color:black; border-top-width:1px; text-align:center; border-right:1px solid black" 
        rowspan=""
        colspan="">
      <p>\(\frac{1+(\beta -1)\theta _k+\beta \theta _k^2}{1+(\beta -2-\frac{1}{1+\gamma \phi _k})\theta _k+\frac{\beta -2}{1+\gamma \phi _k}\theta _k^2}\)</p>

    </td>
    <td  style="border-top-style:solid; border-top-color:black; border-top-width:1px; text-align:center; border-right:1px solid black" 
        rowspan=""
        colspan="">
      <p>King’s type (K8) <span class="cite">
	[
	
	<a href="#6" >7</a>
	
	]
</span></p>

    </td>
  </tr>
  <tr>
    <td  style="border-top-style:solid; border-top-color:black; border-top-width:1px; text-align:left; border-left:1px solid black" 
        rowspan=""
        colspan="">
      
<p>\(1\)</p>

    </td>
    <td  style="border-top-style:solid; border-top-color:black; border-top-width:1px; text-align:center" 
        rowspan=""
        colspan="">
      <p>\(-\frac{1}{1+\gamma \phi _n}\) </p>

    </td>
    <td  style="border-top-style:solid; border-top-color:black; border-top-width:1px; text-align:center" 
        rowspan=""
        colspan="">
      <p> \(0\) </p>

    </td>
    <td  style="border-top-style:solid; border-top-color:black; border-top-width:1px; text-align:center; border-right:1px solid black" 
        rowspan=""
        colspan="">
      <p>\(0\)</p>

    </td>
    <td  style="border-top-style:solid; border-top-color:black; border-top-width:1px; text-align:center; border-right:1px solid black" 
        rowspan=""
        colspan="">
      <p>\(\frac{1+\theta _n}{1-\frac{\theta _n}{1+\gamma \phi _n}}\)</p>

    </td>
    <td  style="border-top-style:solid; border-top-color:black; border-top-width:1px; text-align:center; border-right:1px solid black" 
        rowspan=""
        colspan="">
      <p>Sharma (S8)<span class="cite">
	[
	
	<a href="#7" >9</a>
	
	]
</span></p>

    </td>
  </tr>
  <tr>
    <td  style="border-top-style:solid; border-top-color:black; border-top-width:1px; text-align:left; border-left:1px solid black" 
        rowspan=""
        colspan="">
      <p>\(1\)</p>

    </td>
    <td  style="border-top-style:solid; border-top-color:black; border-top-width:1px; text-align:center" 
        rowspan=""
        colspan="">
      <p>\(-2\alpha -\frac{1}{1+\gamma \phi _n}\)</p>

    </td>
    <td  style="border-top-style:solid; border-top-color:black; border-top-width:1px; text-align:center" 
        rowspan=""
        colspan="">
      <p>\(\frac{2\alpha }{1+\gamma \phi _n}\)</p>

    </td>
    <td  style="border-top-style:solid; border-top-color:black; border-top-width:1px; text-align:center; border-right:1px solid black" 
        rowspan=""
        colspan="">
      <p>\(H(\theta _n)\)</p>

    </td>
    <td  style="border-top-style:solid; border-top-color:black; border-top-width:1px; text-align:center; border-right:1px solid black" 
        rowspan=""
        colspan="">
      <p>\(\frac{1}{1-2\alpha \theta _n}\frac{H(\theta _n)}{(1-\frac{\theta _n}{1+\gamma \phi _n})}\)</p>

    </td>
    <td  style="border-top-style:solid; border-top-color:black; border-top-width:1px; text-align:center; border-right:1px solid black" 
        rowspan=""
        colspan="">
      <p>Chebyshev-Halley (CH8)<span class="cite">
	[
	
	<a href="#1" >1</a>
	
	]
</span></p>

    </td>
  </tr>
  <tr>
    <td  style="border-top-style:solid; border-top-color:black; border-top-width:1px; text-align:left; border-left:1px solid black" 
        rowspan=""
        colspan="">
      <p>\(1\)</p>

    </td>
    <td  style="border-top-style:solid; border-top-color:black; border-top-width:1px; text-align:center" 
        rowspan=""
        colspan="">
      <p>\(-\hat{d}_n\)</p>

    </td>
    <td  style="border-top-style:solid; border-top-color:black; border-top-width:1px; text-align:center" 
        rowspan=""
        colspan="">
      <p>\(\frac{\hat{d}_n^2}{4}\)</p>

    </td>
    <td  style="border-top-style:solid; border-top-color:black; border-top-width:1px; text-align:center; border-right:1px solid black" 
        rowspan=""
        colspan="">
      <p>\(0\)</p>

    </td>
    <td  style="border-top-style:solid; border-top-color:black; border-top-width:1px; text-align:center; border-right:1px solid black" 
        rowspan=""
        colspan="">
      <p>\(\frac{1}{(1-\frac{\hat{d}_n}{2}\theta _n)^2}\)</p>

    </td>
    <td  style="border-top-style:solid; border-top-color:black; border-top-width:1px; text-align:center; border-right:1px solid black" 
        rowspan=""
        colspan="">
      <p> <span class="cite">
	[
	
	<a href="#3'" >4</a>
	
	]
</span></p>

    </td>
  </tr>
  <tr>
    <td  style="border-top-style:solid; border-top-color:black; border-top-width:1px; text-align:left; border-left:1px solid black" 
        rowspan=""
        colspan="">
      <p>\(1\)</p>

    </td>
    <td  style="border-top-style:solid; border-top-color:black; border-top-width:1px; text-align:center" 
        rowspan=""
        colspan="">
      <p>\(-\hat{d}_n\)</p>

    </td>
    <td  style="border-top-style:solid; border-top-color:black; border-top-width:1px; text-align:center" 
        rowspan=""
        colspan="">
      <p>\(\frac{1}{1+\gamma \phi _n}\)</p>

    </td>
    <td  style="border-top-style:solid; border-top-color:black; border-top-width:1px; text-align:center; border-right:1px solid black" 
        rowspan=""
        colspan="">
      <p>0</p>

    </td>
    <td  style="border-top-style:solid; border-top-color:black; border-top-width:1px; text-align:center; border-right:1px solid black" 
        rowspan=""
        colspan="">
      <p>\(\frac{1}{1-\hat{d}_n\theta _n+\frac{1}{1+\gamma \phi _n}\theta _n^2}\)</p>

    </td>
    <td  style="border-top-style:solid; border-top-color:black; border-top-width:1px; text-align:center; border-right:1px solid black" 
        rowspan=""
        colspan="">
      <p> Thukral (T8)<span class="cite">
	[
	
	<a href="#7''" >12</a>
	
	]
</span></p>

    </td>
  </tr>
  <tr>
    <td  style="text-align:left; border-left:1px solid black" 
        rowspan=""
        colspan="">&nbsp;</td>
    <td  style="text-align:center" 
        rowspan=""
        colspan="">&nbsp;</td>
    <td  style="text-align:center" 
        rowspan=""
        colspan="">&nbsp;</td>
    <td  style="text-align:center; border-right:1px solid black" 
        rowspan=""
        colspan="">&nbsp;</td>
    <td  style="text-align:center; border-right:1px solid black" 
        rowspan=""
        colspan="">&nbsp;</td>
    <td  style="border-top-style:solid; border-top-color:black; border-top-width:1px; text-align:center; border-right:1px solid black" 
        rowspan=""
        colspan="">
      <p> Kung-Traub (KT8)<span class="cite">
	[
	
	<a href="#12" >17</a>
	
	]
</span></p>

    </td>
  </tr>
  <tr>
    <td  style="border-top-style:solid; border-top-color:black; border-top-width:1px; text-align:left; border-left:1px solid black" 
        rowspan=""
        colspan="">
      <p>\(1\)</p>

    </td>
    <td  style="border-top-style:solid; border-top-color:black; border-top-width:1px; text-align:center" 
        rowspan=""
        colspan="">
      <p>\(-\hat{d}_n\)</p>

    </td>
    <td  style="border-top-style:solid; border-top-color:black; border-top-width:1px; text-align:center" 
        rowspan=""
        colspan="">
      <p>\(\frac{1}{1-\phi _n}\)</p>

    </td>
    <td  style="border-top-style:solid; border-top-color:black; border-top-width:1px; text-align:center; border-right:1px solid black" 
        rowspan=""
        colspan="">
      <p>0</p>

    </td>
    <td  style="border-top-style:solid; border-top-color:black; border-top-width:1px; text-align:center; border-right:1px solid black" 
        rowspan=""
        colspan="">
      <p>\(\frac{1}{(1-\frac{\theta _n}{1-\phi _n})(1-\theta _n)}\) </p>

    </td>
    <td  style="border-top-style:solid; border-top-color:black; border-top-width:1px; text-align:center; border-right:1px solid black" 
        rowspan=""
        colspan="">
      <p> Soleymani (SS8) <span class="cite">
	[
	
	<a href="#7'" >10</a>
	
	]
</span> </p>

    </td>
  </tr>
  <tr>
    <td  style="border-top-style:solid; border-top-color:black; border-top-width:1px; text-align:left; border-left:1px solid black" 
        rowspan=""
        colspan="">
      <p>\(1\)</p>

    </td>
    <td  style="border-top-style:solid; border-top-color:black; border-top-width:1px; text-align:center" 
        rowspan=""
        colspan="">
      <p>\(-1\)</p>

    </td>
    <td  style="border-top-style:solid; border-top-color:black; border-top-width:1px; text-align:center" 
        rowspan=""
        colspan="">
      <p>0</p>

    </td>
    <td  style="border-top-style:solid; border-top-color:black; border-top-width:1px; text-align:center; border-right:1px solid black" 
        rowspan=""
        colspan="">
      <p>\(\frac{1}{(1+\gamma \phi _n)^2}\)</p>

    </td>
    <td  style="border-top-style:solid; border-top-color:black; border-top-width:1px; text-align:center; border-right:1px solid black" 
        rowspan=""
        colspan="">
      <p>\((1+\frac{\theta _n}{(1+\gamma \phi _n)}+\frac{\theta _n^2}{(1+\gamma \phi _n)^2})\frac{1}{1-\theta _n}\)</p>

    </td>
    <td  style="border-top-style:solid; border-top-color:black; border-top-width:1px; text-align:center; border-right:1px solid black" 
        rowspan=""
        colspan="">
      <p>Soleymani (SV8) <span class="cite">
	[
	
	<a href="#77" >11</a>
	
	]
</span></p>

    </td>
  </tr>
  <tr>
    <td  style="border-top-style:solid; border-top-color:black; border-top-width:1px; text-align:left; border-left:1px solid black; border-bottom-style:solid; border-bottom-color:black; border-bottom-width:1px" 
        rowspan=""
        colspan="">
      <p>1</p>

    </td>
    <td  style="border-top-style:solid; border-top-color:black; border-top-width:1px; text-align:center; border-bottom-style:solid; border-bottom-color:black; border-bottom-width:1px" 
        rowspan=""
        colspan="">
      <p>\(-\hat{d}_n\)</p>

    </td>
    <td  style="border-top-style:solid; border-top-color:black; border-top-width:1px; text-align:center; border-bottom-style:solid; border-bottom-color:black; border-bottom-width:1px" 
        rowspan=""
        colspan="">
      <p>\(-\frac{1}{1+\gamma \phi _n}\)</p>

    </td>
    <td  style="border-top-style:solid; border-top-color:black; border-top-width:1px; text-align:center; border-right:1px solid black; border-bottom-style:solid; border-bottom-color:black; border-bottom-width:1px" 
        rowspan=""
        colspan="">
      <p>\(0\)</p>

    </td>
    <td  style="border-top-style:solid; border-top-color:black; border-top-width:1px; text-align:center; border-right:1px solid black; border-bottom-style:solid; border-bottom-color:black; border-bottom-width:1px" 
        rowspan=""
        colspan="">
      <p>\(\frac{1}{1-\hat{d}_n\theta _n-\frac{\theta _n^2}{1+\gamma \phi _n}}\)</p>

    </td>
    <td  style="border-top-style:solid; border-top-color:black; border-top-width:1px; text-align:center; border-right:1px solid black; border-bottom-style:solid; border-bottom-color:black; border-bottom-width:1px" 
        rowspan=""
        colspan="">
      <p>M1</p>

    </td>
  </tr>
</table> <figcaption>
  <span class="caption_title">Table</span> 
  <span class="caption_ref">1</span> 
  <span class="caption_text">Choices of parameters for methods.</span> 
</figcaption>  </small></div>
</div>
<p> Moreover, the iteration (<a href="#2.17">18</a>) can be rewritten as </p>
<div class="displaymath" id="2.18">
  \begin{eqnarray} \label{2.18} & & y_n=x_n-\tfrac {f(x_n)}{f[x_n,w_n]},\quad w_n=x_n+\gamma f(x_n),\quad \gamma \in \mathbb {R} \setminus \{ 0\}  \nonumber \\ & & z_n=\psi _4(x_n,y_n,z_n),\\ & & x_{n+1}=z_n-\tfrac {f(z_n)}{f[z_n,y_n]+(z_n-y_n)f[z_n,y_n,x_n]+(z_n-y_n)F}\nonumber , \end{eqnarray}
</div>
<p> where \(\psi _4\) is any optimal fourth order derivative-free method. From (<a href="#2.18">19</a>) we see that the each iteration of the family of derivative-free optimal three-point iterations (<a href="#2.18">19</a>) essentially depends on the choice \(\psi _4\) or the choice of iteration parameter \(\bar{\tau }_n\) in (<a href="#2.17">18</a>). </p>
<h1 id="sec3">3 Convergence analysis</h1>
<p>  Generally, the convergence properties of family of iterations (<a href="#2.17">18</a>) essentially depend on the convergence of iterations consisting of the first two sub-steps in (<a href="#2.17">18</a>) <i class="itshape">i</i>.e., </p>
<div class="displaymath" id="3.20">
  \begin{eqnarray} \label{3.20} & &  y_n=x_n-\tfrac {f(x_n)}{f[x_n,w_n]},\nonumber \\ & &  z_n=y_n-\bar{\tau }_n\tfrac {f(y_n)}{f[x_n,w_n]}, \end{eqnarray}
</div>
<p> where \(\bar{\tau }_n\) is given by (<a href="#2.10">8</a>). It is easy to show that if the iterations (<a href="#3.20">20</a>) converge then its convergence order is four. Moreover, if the iterations (<a href="#3.20">20</a>) converge, so does (<a href="#2.17">18</a>) with convergence order eight. From this clear that in order to establish the convergence of (<a href="#2.17">18</a>) it suffice to establish the convergence of iterations (<a href="#3.20">20</a>). To this end we use Taylor expansion of function \(f\in C^2(I)\) and another form of second-step in (<a href="#3.20">20</a>) as </p>
<div class="displaymath" id="3.21">
  \begin{eqnarray} \label{3.21} z_n=x_n-\tau _n\frac{f(x_n)}{\phi _n},\quad \tau _n=1+\bar{\tau }_n\theta _n. \end{eqnarray}
</div>
<p> As a result, we have </p>
<div class="displaymath" id="3.22">
  \begin{eqnarray} \label{3.22} f(z_n)=\Big(1-\frac{f'(x_n)}{\phi _n}\tau _n+\frac{w_n}{2}\frac{f'(x_n)^2}{\phi ^2_n}\tau _n^2\Big)f(x_n). \end{eqnarray}
</div>
<p> where </p>
<div class="displaymath" id="3.23">
  \begin{eqnarray} \label{3.23} w_n=\frac{f''(\xi _n)f(x_n)}{f'(x_n)^2}. \end{eqnarray}
</div>
<p> From (<a href="#3.22">22</a>) it follows </p>
<div class="displaymath" id="3.24">
  \begin{eqnarray} \label{3.24} |f(z_n)|\leq \bar{q}|f(x_n)|, \end{eqnarray}
</div>
<p> where </p>
<div class="displaymath" id="3.25">
  \begin{eqnarray} \label{3.25} \bar{q}=|1-\eta _n+\frac{w_n}{2}\eta ^2_n|, \quad \eta _n=\frac{f'(x_n)}{\phi _n}\tau _n. \end{eqnarray}
</div>
<p> From (<a href="#3.24">24</a>) we see that the convergence of iterations (<a href="#3.20">20</a>) is expected only when </p>
<div class="displaymath" id="3.26">
  \begin{eqnarray} \label{3.26} \bar{q}{\lt} 1. \end{eqnarray}
</div>
<p> Thus, it suffice to find conditions for which (<a href="#3.26">26</a>) holds true. It is easy to prove that </p>
<p><div class="lemma_thmwrapper " id="lm1">
  <div class="lemma_thmheading">
    <span class="lemma_thmcaption">
    Lemma
    </span>
    <span class="lemma_thmlabel">1</span>
  </div>
  <div class="lemma_thmcontent">
  <p> Let the \(w_n\in (-2,1).\) Then the inequality <a href="#3.26" class="eqref">26</a> holds true under conditions: </p>

<div class="displaymath" id="a0000000005">
  \begin{eqnarray} & & 0{\lt}\eta _n{\lt} 2\qquad \text{when}\qquad 0{\lt}w_n{\lt}1,\\ & & 0{\lt}\eta _n{\lt} 1\qquad \text{when}\qquad -2{\lt}w_n{\lt}0. \end{eqnarray}
</div>


  </div>
</div> </p>
<p><div class="theorem_thmwrapper " id="th2">
  <div class="theorem_thmheading">
    <span class="theorem_thmcaption">
    Theorem
    </span>
    <span class="theorem_thmlabel">2</span>
  </div>
  <div class="theorem_thmcontent">
  <p> Let \(1+\gamma \phi _n{\gt}0\) and \(w_n\in (-2,1).\) Then the two-point iterative methods <a href="#3.20" class="eqref">20</a> converge under condition </p>
<div class="displaymath" id="3.28">
  \begin{eqnarray} \label{3.28} |\theta _n|{\lt}1+\gamma \phi _n. \end{eqnarray}
</div>
<p>. </p>

  </div>
</div> <div class="proof_wrapper" id="a0000000006">
  <div class="proof_heading">
    <span class="proof_caption">
    Proof
    </span>
    <span class="expand-proof">â–¼</span>
  </div>
  <div class="proof_content">
  
  </div>
</div> Using the following relations </p>
<div class="displaymath" id="a0000000007">
  \begin{eqnarray*}  \frac{f'(x_n)}{\phi _n}=1-\frac{\gamma \phi _n}{1+\gamma \phi _n}\theta _n+\mathcal{O}(f^2_n), \end{eqnarray*}
</div>
<p> and </p>
<div class="displaymath" id="a0000000008">
  \begin{eqnarray*}  \tau _n=1+\theta _n+\hat{d}_n\theta _n^2+\dots , \end{eqnarray*}
</div>
<p> in (<a href="#3.25">25</a>) we obtain </p>
<div class="displaymath" id="3.29">
  \begin{eqnarray} \label{3.29} \eta _n=1+\frac{1}{1+\gamma \phi _n}\theta _n+\mathcal{O}(f^2_n). \end{eqnarray}
</div>
<p> If we use (<a href="#3.29">31</a>) then the condition (<a href="#3.27">27</a>) can be written in term of \(\theta _n\) as (<a href="#3.28">30</a>) within the accuracy \(\mathcal{O}(f^2(x_n))\). In other words, (<a href="#3.26">26</a>) holds true under condition (<a href="#3.28">30</a>). <div class="proof_wrapper" id="a0000000009">
  <div class="proof_heading">
    <span class="proof_caption">
    Proof
    </span>
    <span class="expand-proof">â–¼</span>
  </div>
  <div class="proof_content">
  
  </div>
</div> From (<a href="#2.10">8</a>) we obtain </p>
<div class="displaymath" id="3.30">
  \begin{eqnarray} \label{3.30} \bar{\tau }_n-1=\frac{\theta _n(\hat{d}_n c+(\omega -b) \theta _n)}{c+d\theta _n+b\theta _n^2}=\frac{\theta _n\varphi (\theta _n)}{c+d\theta _n+b\theta _n^2}, \end{eqnarray}
</div>
<p> where </p>
<div class="displaymath" id="a0000000010">
  \begin{eqnarray*}  \varphi (\theta _n)=\hat{d}_n c+(\omega -b)\theta _n. \end{eqnarray*}
</div>
<p> Let \(|\omega -b|{\lt}\hat{d}_n c\). Then \(\varphi (\theta _n){\gt}0\) on \(\theta _n\in [-1,1]\). Then from (<a href="#3.30">32</a>) we deduce that the following relations </p>
<div class="displaymath" id="a0000000011">
  \begin{eqnarray*}  \bar{\tau }_n\rightarrow 1, \quad \theta _n\rightarrow 0, \end{eqnarray*}
</div>
<p> are equivalent and the convergence of sequences \(f(z_n)\) and \(\theta _n\) to zero as \(n\rightarrow \infty \) expected simultaneously with equal order four. On the other hand, the iteration (<a href="#3.20">20</a>) can be considered as damped Newton’s method </p>
<div class="displaymath" id="a0000000012">
  \begin{eqnarray*}  y_n=x_n-\frac{f(x_n)}{f'(x_n)}\eta _n , \end{eqnarray*}
</div>
<p> with damping parameter \(\eta _n \) given by (<a href="#3.28">30</a>). As is known that, the damped Newton’s method converges <span class="cite">
	[
	
	<a href="#10" >15</a>
	
	]
</span> if </p>
<div class="displaymath" id="3.30'">
  \begin{eqnarray} \label{3.30'} 0{\lt}\eta _n {\lt}2. \end{eqnarray}
</div>
<p> In term of \(\theta _n\) the condition (<a href="#3.30'">33</a>) gives the same result (<a href="#3.29">31</a>). </p>
<h1 id="sec4">4 Numerical experiments and dynamical behavior</h1>

<p>In this section, we will give a numerical comparison of our method M1 with other well known optimal eighth order methods listed in <a href="#tab1">table 1</a>. For this purpose, we consider several test functions given in <a href="#tab2">table 2</a>. In particular, \(f_2=0\) is Kepler’s equation which relates the eccentric anomaly \(E\), the mean anomaly \(M\) and the eccentricity \(\epsilon \) in an elliptic orbit. </p>
<div class="table"  id="tab2">
   <div class="centered"><small class="small"> !<table class="tabular">
  <tr>
    <td  style="border-top-style:solid; border-top-color:black; border-top-width:1px; text-align:left; border-bottom-style:solid; border-bottom-color:black; border-bottom-width:1px" 
        rowspan=""
        colspan="">&nbsp;</td>
    <td  style="border-top-style:solid; border-top-color:black; border-top-width:1px; text-align:center; border-bottom-style:solid; border-bottom-color:black; border-bottom-width:1px" 
        rowspan=""
        colspan="">
      <p> Test functions </p>

    </td>
    <td  style="border-top-style:solid; border-top-color:black; border-top-width:1px; text-align:center; border-bottom-style:solid; border-bottom-color:black; border-bottom-width:1px" 
        rowspan=""
        colspan="">
      <p> Roots </p>

    </td>
  </tr>
  <tr>
    <td  style="text-align:left" 
        rowspan=""
        colspan="">
      <p>1. </p>

    </td>
    <td  style="text-align:center" 
        rowspan=""
        colspan="">
      <p>&#160;\(f_1=\exp (-x^2+x+2)+\sin (\pi x)\exp (x^2+x \cos (x)-1)+1\), <span class="cite">
	[
	
	<a href="#5" >6</a>
	
	]
</span> </p>

    </td>
    <td  style="text-align:center" 
        rowspan=""
        colspan="">
      <p> \(x^*\approx 1.55\) </p>

    </td>
  </tr>
  <tr>
    <td  style="text-align:left; border-bottom-style:solid; border-bottom-color:black; border-bottom-width:1px" 
        rowspan=""
        colspan="">
      <p>2. </p>

    </td>
    <td  style="text-align:center; border-bottom-style:solid; border-bottom-color:black; border-bottom-width:1px" 
        rowspan=""
        colspan="">
      <p>\(f_2=M-E+\epsilon \sin (E)\), &#160;\(0{\lt}\epsilon {\lt}1\), <span class="cite">
	[
	
	<a href="#1" >1</a>
	
	]
</span> </p>

    </td>
    <td  style="text-align:center; border-bottom-style:solid; border-bottom-color:black; border-bottom-width:1px" 
        rowspan=""
        colspan="">
      <p> \( x^*\approx 0.38\) </p>

    </td>
  </tr>
</table> <figcaption>
  <span class="caption_title">Table</span> 
  <span class="caption_ref">2</span> 
  <span class="caption_text">Nonlinear functions.</span> 
</figcaption>  </small></div>
</div>
<p>Additionally, we will make comparison of method M1 and other methods based on the dynamical behaviour. </p>
<p>Further, we will use the abbreviated names for methods (see last column of <a href="#tab1">table 1</a>). In ??, we consider method (CH8) using the weight function \(H(\theta _n)=1+(1-2\alpha )\theta _n\) with values of the parameter \(\alpha =0,\pm 1\) (see <span class="cite">
	[
	
	<a href="#1" >1</a>
	
	]
</span>), method (L8) for \((a=0,\pm 1)\) and method (K8) for \((\beta =0,\pm 1)\). In addition to compare family (<a href="#2.17">18</a>) with other methods we also consider some optimal methods, which third substeps are different from method (<a href="#2.17">18</a>). Namely, we used the following substeps: </p>
<p>Derivative-free Soleymani <i class="itshape">e</i>t al. <span class="cite">
	[
	
	<a href="#77" >11</a>
	
	]
</span> three-step method (SV8) has the following substep: </p>
<div class="displaymath" id="a0000000013">
  \begin{eqnarray*} & & x_{n+1}=z_n-\tfrac {f(z_n)}{f[z_n,y_n]}\Big( 1-\tfrac {1}{f[x_n,w_n]-1}\bigl(\tfrac {f(y_n)}{f(x_n)}\bigr)^2+(2-f[z_n,y_n])\tfrac {f(z_n)}{f(w_n)}\Big). \end{eqnarray*}
</div>
<p> Derivative-free Kung-Traub’s <span class="cite">
	[
	
	<a href="#12" >17</a>
	
	]
</span> three-step method (KT8) has the following substep: </p>
<div class="displaymath" id="a0000000014">
  \begin{eqnarray*} & & x_{n+1}=z_n-\tfrac {f(y_n)f(w_n)(y_n-x_n+f(x_n)/f[x_n,z_n])}{(f(y_n)-f(z_n))(f(w_n)-f(z_n))}. \end{eqnarray*}
</div>
<p>Derivative-free Thukral’s <span class="cite">
	[
	
	<a href="#7''" >12</a>
	
	]
</span> three-step method (T8) has the following sub-step: </p>
<div class="displaymath" id="a0000000015">
  \begin{eqnarray*} & & x_{n+1}=z_n-\Big(1-\tfrac {f(z_n)}{f(w_n)}\Big)^{-1}\\ & & \hspace{1.2cm}\times \Big(1+\tfrac {2f(y_n)^3}{f(w_n)^2f(x_n)}\Big)^{-1} \Big(\tfrac {f(z_n)}{f[z_n,y_n]-f[x_n,y_n]+f[z_n,x_n]}\Big). \end{eqnarray*}
</div>
<p> Derivative-free Soleymani <i class="itshape">e</i>t al. <span class="cite">
	[
	
	<a href="#7'" >10</a>
	
	]
</span> three-step method (SS8) has the following substep: </p>
<div class="displaymath" id="a0000000016">
  \begin{eqnarray*} & & x_{n+1}=z_n-\tfrac {f(z_n)f(w_n)}{(f(w_n)-f(y_n))f[x_n,y_n]}\\ & & \hspace{1.2cm}\times \Big(1+\tfrac {f(z_n)}{f(y_n)}\Big)\Big(1+(2-f[x_n,w_n])\tfrac {f(z_n)}{f(w_n)}\Big)\\ & & \hspace{1.2cm}\times \Big(1+\bigl(\tfrac {f(z_n)}{f(x_n)}\bigr)^2\Big)\Big(1+(1-f[x_n,w_n])\bigl(\tfrac {f(y_n)}{f(w_n)}\bigr)^2\Big). \end{eqnarray*}
</div>
<p>All computations are carried out using Maple18 computer algebra system with 1000 digits. We use the following stopping criterion for the methods:<br />\(|x_n-x^*|\leq \varepsilon \) where \(\varepsilon =10^{-50}\) and \(x^*\) is the exact solution of the considered equation. In all examples, we consider that the parameter \(\gamma =-0.01\). </p>
<p>To check the theoretical order of convergence of methods, we calculated the computational order of convergence \(\rho \) (see <span class="cite">
	[
	-
</span>) using formula </p>
<div class="equation" id="a0000000017">
<p>
  <div class="equation_content">
    \begin{equation} \nonumber \rho \approx \frac{\ln (|x_{n}-x^*| / | x_{n-1}-x^*|)}{\ln (| x_{n-1}-x^*| /|x_{n-2}-x^{*}|)}, \nonumber \end{equation}
  </div>
  <span class="equation_label">34</span>
</p>
</div>
<p> where \(x_{n} , x_{n-1} , x_{n-2}\) are last three consecutive approximations in the iteration process. In ??, we use test functions \(f_1\), \(f_2\), \(f_3\) and exhibit the iteration numbers \(n\), the absolute value \(|x_{n}-x^*|\) and the computational order of convergence \(\rho \). When the iteration diverges for the considered initial guess \(x_0\), we denote it by \('-'\). From ?? we see that the convergence order of all the methods in <a href="#tab1">table 1</a> confirmed by numerical experiments. From the result of ??, we can observe that the region of convergence of methods M1 and Z8 are wider than that of other considered methods. </p>
<div class="table"  id="tab3">
   <div class="centered"><table class="tabular">
  <tr>
    <td  style="border-top-style:solid; border-top-color:black; border-top-width:1px; text-align:left" 
        rowspan=""
        colspan="">
      <p> Methods</p>

    </td>
    <td  style="border-top-style:solid; border-top-color:black; border-top-width:1px; text-align:left" 
        rowspan=""
        colspan="">&nbsp;</td>
    <td  style="border-top-style:solid; border-top-color:black; border-top-width:1px; text-align:left" 
        rowspan=""
        colspan="">
      <p>\(n\) </p>

    </td>
    <td  style="border-top-style:solid; border-top-color:black; border-top-width:1px; text-align:center" 
        rowspan=""
        colspan="">
      <p>\(|x_n-x^*|\) </p>

    </td>
    <td  style="border-top-style:solid; border-top-color:black; border-top-width:1px; text-align:center" 
        rowspan=""
        colspan="">
      <p>\(\rho \) </p>

    </td>
    <td  style="border-top-style:solid; border-top-color:black; border-top-width:1px; text-align:center" 
        rowspan=""
        colspan="">
      <p>\(n\) </p>

    </td>
    <td  style="border-top-style:solid; border-top-color:black; border-top-width:1px; text-align:center" 
        rowspan=""
        colspan="">
      <p>\(|x_n-x^*|\) </p>

    </td>
    <td  style="border-top-style:solid; border-top-color:black; border-top-width:1px; text-align:center" 
        rowspan=""
        colspan="">
      <p>\(\rho \) </p>

    </td>
  </tr>
  <tr>
    <td  style="border-top-style:solid; border-top-color:black; border-top-width:1px; text-align:left" 
        rowspan=""
        colspan="">&nbsp;</td>
    <td  style="border-top-style:solid; border-top-color:black; border-top-width:1px; text-align:left" 
        rowspan=""
        colspan="">&nbsp;</td>
    <td  style="border-top-style:solid; border-top-color:black; border-top-width:1px; text-align:left" 
        rowspan=""
        colspan="2">
      <p>\(x^*=1.55\)&#8195;\(x_0=0.8\) </p>

    </td>
    <td  style="border-top-style:solid; border-top-color:black; border-top-width:1px; text-align:center" 
        rowspan=""
        colspan="">&nbsp;</td>
    <td  style="border-top-style:solid; border-top-color:black; border-top-width:1px; text-align:center" 
        rowspan=""
        colspan="">&nbsp;</td>
    <td  style="border-top-style:solid; border-top-color:black; border-top-width:1px; text-align:left" 
        rowspan=""
        colspan="2">
      <p>\(x^*=1.55\)&#8195;\(x_0=1\) </p>

    </td>
  </tr>
  <tr>
    <td  style="text-align:left" 
        rowspan=""
        colspan="">
      <p>M1 </p>

    </td>
    <td  style="text-align:left" 
        rowspan=""
        colspan="">&nbsp;</td>
    <td  style="text-align:left" 
        rowspan=""
        colspan="">
      <p>3 </p>

    </td>
    <td  style="text-align:center" 
        rowspan=""
        colspan="">
      <p>0.5590e-58 </p>

    </td>
    <td  style="text-align:center" 
        rowspan=""
        colspan="">
      <p>7.94 </p>

    </td>
    <td  style="text-align:center" 
        rowspan=""
        colspan="">
      <p>3 </p>

    </td>
    <td  style="text-align:center" 
        rowspan=""
        colspan="">
      <p>0.3688e-69 </p>

    </td>
    <td  style="text-align:center" 
        rowspan=""
        colspan="">
      <p>7.98</p>

    </td>
  </tr>
  <tr>
    <td  style="text-align:left" 
        rowspan=""
        colspan="">
      <p>Z8 </p>

    </td>
    <td  style="text-align:left" 
        rowspan=""
        colspan="">&nbsp;</td>
    <td  style="text-align:left" 
        rowspan=""
        colspan="">&nbsp;</td>
    <td  style="text-align:center" 
        rowspan=""
        colspan="">
      <p> \(-\) </p>

    </td>
    <td  style="text-align:center" 
        rowspan=""
        colspan="">
      <p> \(-\) </p>

    </td>
    <td  style="text-align:center" 
        rowspan=""
        colspan="">
      <p>3 </p>

    </td>
    <td  style="text-align:center" 
        rowspan=""
        colspan="">
      <p> 0.8486e-64 </p>

    </td>
    <td  style="text-align:center" 
        rowspan=""
        colspan="">
      <p>7.93 </p>

    </td>
  </tr>
  <tr>
    <td  style="text-align:left" 
        rowspan=""
        colspan="">
      <p>L8 </p>

    </td>
    <td  style="text-align:left" 
        rowspan=""
        colspan="">
      <p> \((a=0 )\) </p>

    </td>
    <td  style="text-align:left" 
        rowspan=""
        colspan="">&nbsp;</td>
    <td  style="text-align:center" 
        rowspan=""
        colspan="">
      <p> \(-\) </p>

    </td>
    <td  style="text-align:center" 
        rowspan=""
        colspan="">
      <p> \(-\) </p>

    </td>
    <td  style="text-align:center" 
        rowspan=""
        colspan="">
      <p>3 </p>

    </td>
    <td  style="text-align:center" 
        rowspan=""
        colspan="">
      <p> 0.2124e-57 </p>

    </td>
    <td  style="text-align:center" 
        rowspan=""
        colspan="">
      <p>7.88 </p>

    </td>
  </tr>
  <tr>
    <td  style="text-align:left" 
        rowspan=""
        colspan="">&nbsp;</td>
    <td  style="text-align:left" 
        rowspan=""
        colspan="">
      <p> \((a=-1)\) </p>

    </td>
    <td  style="text-align:left" 
        rowspan=""
        colspan="">&nbsp;</td>
    <td  style="text-align:center" 
        rowspan=""
        colspan="">
      <p> \(-\) </p>

    </td>
    <td  style="text-align:center" 
        rowspan=""
        colspan="">
      <p> \(-\) </p>

    </td>
    <td  style="text-align:center" 
        rowspan=""
        colspan="">
      <p>3 </p>

    </td>
    <td  style="text-align:center" 
        rowspan=""
        colspan="">
      <p> 0.4607e-55 </p>

    </td>
    <td  style="text-align:center" 
        rowspan=""
        colspan="">
      <p>7.86 </p>

    </td>
  </tr>
  <tr>
    <td  style="text-align:left" 
        rowspan=""
        colspan="">&nbsp;</td>
    <td  style="text-align:left" 
        rowspan=""
        colspan="">
      <p> \((a=1)\) </p>

    </td>
    <td  style="text-align:left" 
        rowspan=""
        colspan="">&nbsp;</td>
    <td  style="text-align:center" 
        rowspan=""
        colspan="">
      <p> \(-\) </p>

    </td>
    <td  style="text-align:center" 
        rowspan=""
        colspan="">
      <p> \(-\) </p>

    </td>
    <td  style="text-align:center" 
        rowspan=""
        colspan="">
      <p>3 </p>

    </td>
    <td  style="text-align:center" 
        rowspan=""
        colspan="">
      <p> 0.4097e-60 </p>

    </td>
    <td  style="text-align:center" 
        rowspan=""
        colspan="">
      <p>7.91 </p>

    </td>
  </tr>
  <tr>
    <td  style="text-align:left" 
        rowspan=""
        colspan="">
      <p>K8 </p>

    </td>
    <td  style="text-align:left" 
        rowspan=""
        colspan="">
      <p> \((\beta =0)\) </p>

    </td>
    <td  style="text-align:left" 
        rowspan=""
        colspan="">&nbsp;</td>
    <td  style="text-align:center" 
        rowspan=""
        colspan="">
      <p> \(-\) </p>

    </td>
    <td  style="text-align:center" 
        rowspan=""
        colspan="">
      <p> \(-\) </p>

    </td>
    <td  style="text-align:center" 
        rowspan=""
        colspan="">
      <p>3 </p>

    </td>
    <td  style="text-align:center" 
        rowspan=""
        colspan="">
      <p> 0.2369e-64 </p>

    </td>
    <td  style="text-align:center" 
        rowspan=""
        colspan="">
      <p>7.93 </p>

    </td>
  </tr>
  <tr>
    <td  style="text-align:left" 
        rowspan=""
        colspan="">&nbsp;</td>
    <td  style="text-align:left" 
        rowspan=""
        colspan="">
      <p> \((\beta =-1)\) </p>

    </td>
    <td  style="text-align:left" 
        rowspan=""
        colspan="">&nbsp;</td>
    <td  style="text-align:center" 
        rowspan=""
        colspan="">
      <p> \(-\) </p>

    </td>
    <td  style="text-align:center" 
        rowspan=""
        colspan="">
      <p> \(-\) </p>

    </td>
    <td  style="text-align:center" 
        rowspan=""
        colspan="">
      <p>3 </p>

    </td>
    <td  style="text-align:center" 
        rowspan=""
        colspan="">
      <p> 0.7934e-65 </p>

    </td>
    <td  style="text-align:center" 
        rowspan=""
        colspan="">
      <p>7.92 </p>

    </td>
  </tr>
  <tr>
    <td  style="text-align:left" 
        rowspan=""
        colspan="">&nbsp;</td>
    <td  style="text-align:left" 
        rowspan=""
        colspan="">
      <p> \((\beta =1)\) </p>

    </td>
    <td  style="text-align:left" 
        rowspan=""
        colspan="">&nbsp;</td>
    <td  style="text-align:center" 
        rowspan=""
        colspan="">
      <p> \(-\) </p>

    </td>
    <td  style="text-align:center" 
        rowspan=""
        colspan="">
      <p> \(-\) </p>

    </td>
    <td  style="text-align:center" 
        rowspan=""
        colspan="">
      <p>3 </p>

    </td>
    <td  style="text-align:center" 
        rowspan=""
        colspan="">
      <p> 0.4687e-64 </p>

    </td>
    <td  style="text-align:center" 
        rowspan=""
        colspan="">
      <p>7.94 </p>

    </td>
  </tr>
  <tr>
    <td  style="text-align:left" 
        rowspan=""
        colspan="">
      <p>S8 </p>

    </td>
    <td  style="text-align:left" 
        rowspan=""
        colspan="">&nbsp;</td>
    <td  style="text-align:left" 
        rowspan=""
        colspan="">&nbsp;</td>
    <td  style="text-align:center" 
        rowspan=""
        colspan="">
      <p> \(-\) </p>

    </td>
    <td  style="text-align:center" 
        rowspan=""
        colspan="">
      <p> \(-\) </p>

    </td>
    <td  style="text-align:center" 
        rowspan=""
        colspan="">
      <p>3 </p>

    </td>
    <td  style="text-align:center" 
        rowspan=""
        colspan="">
      <p> 0.2124e-57 </p>

    </td>
    <td  style="text-align:center" 
        rowspan=""
        colspan="">
      <p>7.88 </p>

    </td>
  </tr>
  <tr>
    <td  style="text-align:left" 
        rowspan=""
        colspan="">
      <p>CH8 </p>

    </td>
    <td  style="text-align:left" 
        rowspan=""
        colspan="">
      <p> \((\alpha =0)\) </p>

    </td>
    <td  style="text-align:left" 
        rowspan=""
        colspan="">&nbsp;</td>
    <td  style="text-align:center" 
        rowspan=""
        colspan="">
      <p> \(-\) </p>

    </td>
    <td  style="text-align:center" 
        rowspan=""
        colspan="">
      <p> \(-\) </p>

    </td>
    <td  style="text-align:center" 
        rowspan=""
        colspan="">
      <p>3 </p>

    </td>
    <td  style="text-align:center" 
        rowspan=""
        colspan="">
      <p> 0.2734e-60 </p>

    </td>
    <td  style="text-align:center" 
        rowspan=""
        colspan="">
      <p>7.90 </p>

    </td>
  </tr>
  <tr>
    <td  style="text-align:left" 
        rowspan=""
        colspan="">&nbsp;</td>
    <td  style="text-align:left" 
        rowspan=""
        colspan="">
      <p> \((\alpha =-1)\) </p>

    </td>
    <td  style="text-align:left" 
        rowspan=""
        colspan="">&nbsp;</td>
    <td  style="text-align:center" 
        rowspan=""
        colspan="">
      <p> \(-\) </p>

    </td>
    <td  style="text-align:center" 
        rowspan=""
        colspan="">
      <p> \(-\) </p>

    </td>
    <td  style="text-align:center" 
        rowspan=""
        colspan="">
      <p>3 </p>

    </td>
    <td  style="text-align:center" 
        rowspan=""
        colspan="">
      <p> 0.1654e-54 </p>

    </td>
    <td  style="text-align:center" 
        rowspan=""
        colspan="">
      <p>7.85 </p>

    </td>
  </tr>
  <tr>
    <td  style="text-align:left" 
        rowspan=""
        colspan="">&nbsp;</td>
    <td  style="text-align:left" 
        rowspan=""
        colspan="">
      <p> \((\alpha =1)\) </p>

    </td>
    <td  style="text-align:left" 
        rowspan=""
        colspan="">&nbsp;</td>
    <td  style="text-align:center" 
        rowspan=""
        colspan="">
      <p> \(-\) </p>

    </td>
    <td  style="text-align:center" 
        rowspan=""
        colspan="">
      <p> \(-\) </p>

    </td>
    <td  style="text-align:center" 
        rowspan=""
        colspan="">
      <p>3 </p>

    </td>
    <td  style="text-align:center" 
        rowspan=""
        colspan="">
      <p> 0.1648e-70 </p>

    </td>
    <td  style="text-align:center" 
        rowspan=""
        colspan="">
      <p>7.97 </p>

    </td>
  </tr>
  <tr>
    <td  style="text-align:left" 
        rowspan=""
        colspan="">
      <p><span class="cite">
	[
	
	<a href="#3'" >4</a>
	
	]
</span> </p>

    </td>
    <td  style="text-align:left" 
        rowspan=""
        colspan="">&nbsp;</td>
    <td  style="text-align:left" 
        rowspan=""
        colspan="">&nbsp;</td>
    <td  style="text-align:center" 
        rowspan=""
        colspan="">
      <p> \(-\) </p>

    </td>
    <td  style="text-align:center" 
        rowspan=""
        colspan="">
      <p> \(-\) </p>

    </td>
    <td  style="text-align:center" 
        rowspan=""
        colspan="">
      <p>3 </p>

    </td>
    <td  style="text-align:center" 
        rowspan=""
        colspan="">
      <p> 0.2639e-60 </p>

    </td>
    <td  style="text-align:center" 
        rowspan=""
        colspan="">
      <p>7.90 </p>

    </td>
  </tr>
  <tr>
    <td  style="text-align:left" 
        rowspan=""
        colspan="">
      <p>SS8 </p>

    </td>
    <td  style="text-align:left" 
        rowspan=""
        colspan="">&nbsp;</td>
    <td  style="text-align:left" 
        rowspan=""
        colspan="">&nbsp;</td>
    <td  style="text-align:center" 
        rowspan=""
        colspan="">
      <p> \(-\) </p>

    </td>
    <td  style="text-align:center" 
        rowspan=""
        colspan="">
      <p> \(-\) </p>

    </td>
    <td  style="text-align:center" 
        rowspan=""
        colspan="">
      <p>4 </p>

    </td>
    <td  style="text-align:center" 
        rowspan=""
        colspan="">
      <p> 0.8295e-191 </p>

    </td>
    <td  style="text-align:center" 
        rowspan=""
        colspan="">
      <p>7.99</p>

    </td>
  </tr>
  <tr>
    <td  style="text-align:left" 
        rowspan=""
        colspan="">
      <p>T8 </p>

    </td>
    <td  style="text-align:left" 
        rowspan=""
        colspan="">&nbsp;</td>
    <td  style="text-align:left" 
        rowspan=""
        colspan="">&nbsp;</td>
    <td  style="text-align:center" 
        rowspan=""
        colspan="">
      <p> \(-\) </p>

    </td>
    <td  style="text-align:center" 
        rowspan=""
        colspan="">
      <p> \(-\) </p>

    </td>
    <td  style="text-align:center" 
        rowspan=""
        colspan="">
      <p>4 </p>

    </td>
    <td  style="text-align:center" 
        rowspan=""
        colspan="">
      <p> 0.1898e-204 </p>

    </td>
    <td  style="text-align:center" 
        rowspan=""
        colspan="">
      <p>7.99 </p>

    </td>
  </tr>
  <tr>
    <td  style="text-align:left" 
        rowspan=""
        colspan="">
      <p>SV8 </p>

    </td>
    <td  style="text-align:left" 
        rowspan=""
        colspan="">&nbsp;</td>
    <td  style="text-align:left" 
        rowspan=""
        colspan="">&nbsp;</td>
    <td  style="text-align:center" 
        rowspan=""
        colspan="">
      <p> \(-\) </p>

    </td>
    <td  style="text-align:center" 
        rowspan=""
        colspan="">
      <p> \(-\) </p>

    </td>
    <td  style="text-align:center" 
        rowspan=""
        colspan="">
      <p>4 </p>

    </td>
    <td  style="text-align:center" 
        rowspan=""
        colspan="">
      <p> 0.2008e-174 </p>

    </td>
    <td  style="text-align:center" 
        rowspan=""
        colspan="">
      <p>7.99</p>

    </td>
  </tr>
  <tr>
    <td  style="text-align:left; border-bottom-style:solid; border-bottom-color:black; border-bottom-width:1px" 
        rowspan=""
        colspan="">
      <p>KT8 </p>

    </td>
    <td  style="text-align:left; border-bottom-style:solid; border-bottom-color:black; border-bottom-width:1px" 
        rowspan=""
        colspan="">&nbsp;</td>
    <td  style="text-align:left; border-bottom-style:solid; border-bottom-color:black; border-bottom-width:1px" 
        rowspan=""
        colspan="">&nbsp;</td>
    <td  style="text-align:center; border-bottom-style:solid; border-bottom-color:black; border-bottom-width:1px" 
        rowspan=""
        colspan="">
      <p> \(-\) </p>

    </td>
    <td  style="text-align:center; border-bottom-style:solid; border-bottom-color:black; border-bottom-width:1px" 
        rowspan=""
        colspan="">
      <p> \(-\) </p>

    </td>
    <td  style="text-align:center; border-bottom-style:solid; border-bottom-color:black; border-bottom-width:1px" 
        rowspan=""
        colspan="">
      <p>4 </p>

    </td>
    <td  style="text-align:center; border-bottom-style:solid; border-bottom-color:black; border-bottom-width:1px" 
        rowspan=""
        colspan="">
      <p>0.4856e-324 </p>

    </td>
    <td  style="text-align:center; border-bottom-style:solid; border-bottom-color:black; border-bottom-width:1px" 
        rowspan=""
        colspan="">
      <p>8.00</p>

    </td>
  </tr>
</table> <figcaption>
  <span class="caption_title">Table</span> 
  <span class="caption_ref">3</span> 
  <span class="caption_text">Comparison of various iterative methods for \(f_1(x)\) </span> 
</figcaption>  </div>
</div>
<div class="table"  id="tab5">
   <div class="centered"><table class="tabular">
  <tr>
    <td  style="border-top-style:solid; border-top-color:black; border-top-width:1px; text-align:center" 
        rowspan=""
        colspan="">
      <p> Methods</p>

    </td>
    <td  style="border-top-style:solid; border-top-color:black; border-top-width:1px; text-align:left" 
        rowspan=""
        colspan="">&nbsp;</td>
    <td  style="border-top-style:solid; border-top-color:black; border-top-width:1px; text-align:left" 
        rowspan=""
        colspan="">
      <p>\(n\) </p>

    </td>
    <td  style="border-top-style:solid; border-top-color:black; border-top-width:1px; text-align:center" 
        rowspan=""
        colspan="">
      <p>\(|x_n-x^*|\) </p>

    </td>
    <td  style="border-top-style:solid; border-top-color:black; border-top-width:1px; text-align:center" 
        rowspan=""
        colspan="">
      <p>\(\rho \) </p>

    </td>
  </tr>
  <tr>
    <td  style="border-top-style:solid; border-top-color:black; border-top-width:1px; text-align:left" 
        rowspan=""
        colspan="2">
      <p>\(x^*=0.38\)&#8195;\(x_0=1\) </p>

    </td>
    <td  style="border-top-style:solid; border-top-color:black; border-top-width:1px; text-align:left" 
        rowspan=""
        colspan="">&nbsp;</td>
    <td  style="border-top-style:solid; border-top-color:black; border-top-width:1px; text-align:center" 
        rowspan=""
        colspan="">&nbsp;</td>
  </tr>
  <tr>
    <td  style="border-top-style:solid; border-top-color:black; border-top-width:1px; text-align:center" 
        rowspan=""
        colspan="">
      
<p>M1 </p>

    </td>
    <td  style="border-top-style:solid; border-top-color:black; border-top-width:1px; text-align:left" 
        rowspan=""
        colspan="">&nbsp;</td>
    <td  style="text-align:left" 
        rowspan=""
        colspan="">
      <p>3 </p>

    </td>
    <td  style="text-align:center" 
        rowspan=""
        colspan="">
      <p>0.3388e-266 </p>

    </td>
    <td  style="text-align:center" 
        rowspan=""
        colspan="">
      <p>8.00</p>

    </td>
  </tr>
  <tr>
    <td  style="text-align:center" 
        rowspan=""
        colspan="">
      <p>Z8 </p>

    </td>
    <td  style="text-align:left" 
        rowspan=""
        colspan="">&nbsp;</td>
    <td  style="text-align:left" 
        rowspan=""
        colspan="">
      <p>3 </p>

    </td>
    <td  style="text-align:center" 
        rowspan=""
        colspan="">
      <p> 0.4157e-250 </p>

    </td>
    <td  style="text-align:center" 
        rowspan=""
        colspan="">
      <p>8.00 </p>

    </td>
  </tr>
  <tr>
    <td  style="text-align:center" 
        rowspan=""
        colspan="">
      <p>L8 </p>

    </td>
    <td  style="text-align:left" 
        rowspan=""
        colspan="">
      <p> \((a=0 )\) </p>

    </td>
    <td  style="text-align:left" 
        rowspan=""
        colspan="">
      <p>3 </p>

    </td>
    <td  style="text-align:center" 
        rowspan=""
        colspan="">
      <p> 0.1081e-232 </p>

    </td>
    <td  style="text-align:center" 
        rowspan=""
        colspan="">
      <p>8.00 </p>

    </td>
  </tr>
  <tr>
    <td  style="text-align:center" 
        rowspan=""
        colspan="">&nbsp;</td>
    <td  style="text-align:left" 
        rowspan=""
        colspan="">
      <p> \((a=-1)\) </p>

    </td>
    <td  style="text-align:left" 
        rowspan=""
        colspan="">
      <p>3 </p>

    </td>
    <td  style="text-align:center" 
        rowspan=""
        colspan="">
      <p> 0.6929e-256 </p>

    </td>
    <td  style="text-align:center" 
        rowspan=""
        colspan="">
      <p>8.00 </p>

    </td>
  </tr>
  <tr>
    <td  style="text-align:center" 
        rowspan=""
        colspan="">&nbsp;</td>
    <td  style="text-align:left" 
        rowspan=""
        colspan="">
      <p> \((a=1)\) </p>

    </td>
    <td  style="text-align:left" 
        rowspan=""
        colspan="">
      <p>3 </p>

    </td>
    <td  style="text-align:center" 
        rowspan=""
        colspan="">
      <p> 0.2358e-222 </p>

    </td>
    <td  style="text-align:center" 
        rowspan=""
        colspan="">
      <p>8.00 </p>

    </td>
  </tr>
  <tr>
    <td  style="text-align:center" 
        rowspan=""
        colspan="">
      <p>K8 </p>

    </td>
    <td  style="text-align:left" 
        rowspan=""
        colspan="">
      <p> \((\beta =0)\) </p>

    </td>
    <td  style="text-align:left" 
        rowspan=""
        colspan="">
      <p>3 </p>

    </td>
    <td  style="text-align:center" 
        rowspan=""
        colspan="">
      <p> 0.2496e-219 </p>

    </td>
    <td  style="text-align:center" 
        rowspan=""
        colspan="">
      <p>8.00 </p>

    </td>
  </tr>
  <tr>
    <td  style="text-align:center" 
        rowspan=""
        colspan="">&nbsp;</td>
    <td  style="text-align:left" 
        rowspan=""
        colspan="">
      <p> \((\beta =-1)\) </p>

    </td>
    <td  style="text-align:left" 
        rowspan=""
        colspan="">
      <p>3 </p>

    </td>
    <td  style="text-align:center" 
        rowspan=""
        colspan="">
      <p> 0.1278e-252 </p>

    </td>
    <td  style="text-align:center" 
        rowspan=""
        colspan="">
      <p>7.99 </p>

    </td>
  </tr>
  <tr>
    <td  style="text-align:center" 
        rowspan=""
        colspan="">&nbsp;</td>
    <td  style="text-align:left" 
        rowspan=""
        colspan="">
      <p> \((\beta =1)\) </p>

    </td>
    <td  style="text-align:left" 
        rowspan=""
        colspan="">
      <p>3 </p>

    </td>
    <td  style="text-align:center" 
        rowspan=""
        colspan="">
      <p> 0.4075e-217 </p>

    </td>
    <td  style="text-align:center" 
        rowspan=""
        colspan="">
      <p>7.99 </p>

    </td>
  </tr>
  <tr>
    <td  style="text-align:center" 
        rowspan=""
        colspan="">
      <p>S8 </p>

    </td>
    <td  style="text-align:left" 
        rowspan=""
        colspan="">&nbsp;</td>
    <td  style="text-align:left" 
        rowspan=""
        colspan="">
      <p>3 </p>

    </td>
    <td  style="text-align:center" 
        rowspan=""
        colspan="">
      <p> 0.1081e-232 </p>

    </td>
    <td  style="text-align:center" 
        rowspan=""
        colspan="">
      <p>8.00 </p>

    </td>
  </tr>
  <tr>
    <td  style="text-align:center" 
        rowspan=""
        colspan="">
      <p>CH8 </p>

    </td>
    <td  style="text-align:left" 
        rowspan=""
        colspan="">
      <p> \((\alpha =0)\) </p>

    </td>
    <td  style="text-align:left" 
        rowspan=""
        colspan="">
      <p>3 </p>

    </td>
    <td  style="text-align:center" 
        rowspan=""
        colspan="">
      <p> 0.1081e-232 </p>

    </td>
    <td  style="text-align:center" 
        rowspan=""
        colspan="">
      <p>8.00 </p>

    </td>
  </tr>
  <tr>
    <td  style="text-align:center" 
        rowspan=""
        colspan="">&nbsp;</td>
    <td  style="text-align:left" 
        rowspan=""
        colspan="">
      <p> \((\alpha =-1)\) </p>

    </td>
    <td  style="text-align:left" 
        rowspan=""
        colspan="">
      <p>3 </p>

    </td>
    <td  style="text-align:center" 
        rowspan=""
        colspan="">
      <p> 0.6152e-205 </p>

    </td>
    <td  style="text-align:center" 
        rowspan=""
        colspan="">
      <p>7.99 </p>

    </td>
  </tr>
  <tr>
    <td  style="text-align:center" 
        rowspan=""
        colspan="">&nbsp;</td>
    <td  style="text-align:left" 
        rowspan=""
        colspan="">
      <p> \((\alpha =1)\) </p>

    </td>
    <td  style="text-align:left" 
        rowspan=""
        colspan="">
      <p>3 </p>

    </td>
    <td  style="text-align:center" 
        rowspan=""
        colspan="">
      <p> 0.2496e-219 </p>

    </td>
    <td  style="text-align:center" 
        rowspan=""
        colspan="">
      <p>7.99 </p>

    </td>
  </tr>
  <tr>
    <td  style="text-align:center" 
        rowspan=""
        colspan="">
      <p><span class="cite">
	[
	
	<a href="#3'" >4</a>
	
	]
</span> </p>

    </td>
    <td  style="text-align:left" 
        rowspan=""
        colspan="">&nbsp;</td>
    <td  style="text-align:left" 
        rowspan=""
        colspan="">
      <p>3 </p>

    </td>
    <td  style="text-align:center" 
        rowspan=""
        colspan="">
      <p> 0.5045e-221 </p>

    </td>
    <td  style="text-align:center" 
        rowspan=""
        colspan="">
      <p>8.00 </p>

    </td>
  </tr>
  <tr>
    <td  style="text-align:center" 
        rowspan=""
        colspan="">
      <p>SS8 </p>

    </td>
    <td  style="text-align:left" 
        rowspan=""
        colspan="">&nbsp;</td>
    <td  style="text-align:left" 
        rowspan=""
        colspan="">
      <p>3 </p>

    </td>
    <td  style="text-align:center" 
        rowspan=""
        colspan="">
      <p> 0.1295e-199 </p>

    </td>
    <td  style="text-align:center" 
        rowspan=""
        colspan="">
      <p>7.99</p>

    </td>
  </tr>
  <tr>
    <td  style="text-align:center" 
        rowspan=""
        colspan="">
      <p>T8 </p>

    </td>
    <td  style="text-align:left" 
        rowspan=""
        colspan="">&nbsp;</td>
    <td  style="text-align:left" 
        rowspan=""
        colspan="">
      <p>3 </p>

    </td>
    <td  style="text-align:center" 
        rowspan=""
        colspan="">
      <p> 0.2398e-206 </p>

    </td>
    <td  style="text-align:center" 
        rowspan=""
        colspan="">
      <p>7.99 </p>

    </td>
  </tr>
  <tr>
    <td  style="text-align:center" 
        rowspan=""
        colspan="">
      <p>SV8 </p>

    </td>
    <td  style="text-align:left" 
        rowspan=""
        colspan="">&nbsp;</td>
    <td  style="text-align:left" 
        rowspan=""
        colspan="">
      <p>3 </p>

    </td>
    <td  style="text-align:center" 
        rowspan=""
        colspan="">
      <p> 0.2008e-174 </p>

    </td>
    <td  style="text-align:center" 
        rowspan=""
        colspan="">
      <p>7.99</p>

    </td>
  </tr>
  <tr>
    <td  style="text-align:center; border-bottom-style:solid; border-bottom-color:black; border-bottom-width:1px" 
        rowspan=""
        colspan="">
      <p>KT8 </p>

    </td>
    <td  style="text-align:left; border-bottom-style:solid; border-bottom-color:black; border-bottom-width:1px" 
        rowspan=""
        colspan="">&nbsp;</td>
    <td  style="text-align:left; border-bottom-style:solid; border-bottom-color:black; border-bottom-width:1px" 
        rowspan=""
        colspan="">
      <p>3 </p>

    </td>
    <td  style="text-align:center; border-bottom-style:solid; border-bottom-color:black; border-bottom-width:1px" 
        rowspan=""
        colspan="">
      <p>0.4915e-151 </p>

    </td>
    <td  style="text-align:center; border-bottom-style:solid; border-bottom-color:black; border-bottom-width:1px" 
        rowspan=""
        colspan="">
      <p>7.99</p>

    </td>
  </tr>
</table> <figcaption>
  <span class="caption_title">Table</span> 
  <span class="caption_ref">4</span> 
  <span class="caption_text">Comparison of various iterative methods for \(f_2(x)\) </span> 
</figcaption>  </div>
</div>
<p> Generally, higher order convergence methods consist of multi-steps which may use more evaluations of functions than the original one. In this case, multi-point methods may have the extraneous fixed points (black points). In order to find the extraneous fixed points, we rewrite any three–point method as <span class="cite">
	[
	
	<a href="#3'" >4</a>
	
	]
</span>: </p>
<div class="displaymath" id="a0000000018">
  \begin{eqnarray*}  x_{n+1}=x_n-\frac{f(x_n)}{f[x_n,w_n]}H_f(x_n), \end{eqnarray*}
</div>
<p> where \(H_f=1+\theta _n(\bar{\tau }_n+\alpha _n\upsilon _n)\). Clearly, the root \(x^*\) of \(f(x)\) is a fixed point of the method. The points \(\xi \neq x^*\) for which \(H_f(\xi )=0\) are also fixed points of the method. These fixed points are called extraneous fixed points. As we all know, a fixed point \(\xi \) is called: <br /></p>
<ul class="itemize">
  <li><p>attractive if \(|R'(\xi )|{\lt}1,\) </p>
</li>
  <li><p>repulsive if \(|R'(\xi )|{\gt}1,\) </p>
</li>
  <li><p>parabolic if \(|R'(\xi )|=1,\) </p>
</li>
</ul>
<p> where \(R(z)=z-\frac{f(z)}{f[z,w]}H_f(z)\) is the iteration function. </p>
<p>In addition, if \(|R'(\xi )|=0\), the fixed point is superattracting. Now, we will discuss the extraneous fixed points of each method for comparison. To make it easier , we have taken the simple quadratic polynomial \(p(z)=z^2-1\), whose roots are \(z=\pm 1\). </p>
<p>In <a href="#tab6">table 5</a>, we have collected the extraneous fixed points of the methods Z8, KS8, M1.Next nine methods are analyzed and found that they are unable to compare with other methods. These methods have more than \(20\) extraneous fixed points. Therefore, we have not include those results in <a href="#tab6">table 5</a>. For methods Z8 and KS8, we found that the methods have same ten extraneous fixed points. All fixed points are repulsive. </p>
<p>The basin of attraction of iterative methods is another tool for comparing them. Thus, we compare our methods <a href="#2.17" class="eqref">18</a> with other methods by using the basins of attraction for polynomials \(p(z)=z^3-1\). </p>
<p>To illustrate the behavior of the iterative methods, We take \(600 \times 600\) equally spaced points in the square \([-3, 3]\times [-3, 3]\subset C\). In <a href="#fig1:images-H">figure 1</a>, the basin of attraction for \(12\) methods are displayed. The red, green and blue colors are assigned for the attraction basin of the three zeros and the roots of function are marked with white points. Black color is shown lack of convergence to any of the roots. In this cases, the stopping criterion \(\varepsilon =10^{-4}\) and maximum of 25 iterations are used. These dynamical planes have been generated by using the Mathematica 11. From <a href="#fig1:images-H">figure 1</a> and <a href="#tab6">table 5</a>, we can also see that methods M1 and Z8 is much more stable than the others. It can be observed from the figures that the methods M1 along with the existing methods Z8 have wide attraction basins to corresponding zeros than other methods. Z8 also has the least number of black points. <br /></p>
<h1 id="sec5">5 Conclusion</h1>
<p> We have shown that the well-known Khattri <i class="itshape">e</i>t al. <span class="cite">
	[
	
	<a href="#4" >5</a>
	
	]
</span> methods and Zheng <i class="itshape">e</i>t al. <span class="cite">
	[
	
	<a href="#9" >14</a>
	
	]
</span> methods are identical. For the Khattri methods, we propose a suitable calculation formula (<a href="#2.17">18</a>) instead of (<a href="#2.7">5</a>). Our proposed method (<a href="#2.17">18</a>) represents wide class of optimal derivative-free iterations. The method (<a href="#2.17">18</a>) contain some well known iterations as particular cases (see <a href="#tab1">table 1</a>). The comparison of some eighth-order methods was made from the dynamic behavior of view. We observe that the methods M1 and Z8 are much more stable than the others. Note that the family of derivative-free methods (<a href="#2.17">18</a>) can be extended to the systems of nonlinear equations and this study is currently ongoing. <div class="acknowledgement_thmwrapper " id="a0000000019">
  <div class="acknowledgement_thmheading">
    <span class="acknowledgement_thmcaption">
    Acknowledgements
    </span>
  </div>
  <div class="acknowledgement_thmcontent">
  <p>The authors wish to thank the editor and the anonymous referees for their valuable suggestions and comments, which improved paper. This work was supported by the Foundation of Science and Technology of Mongolian under grant SST\(\_ \)18/2018. </p>

  </div>
</div> </p>
<div class="table"  id="tab6">
   <div class="centered"><small class="small"> 0.90 <table class="tabular">
  <tr>
    <td  style="border-top-style:solid; border-top-color:black; border-top-width:1px; text-align:center; border-right:1px solid black; border-left:1px solid black" 
        rowspan=""
        colspan="">
      <p> Methods </p>

    </td>
    <td  style="border-top-style:solid; border-top-color:black; border-top-width:1px; text-align:left; border-right:1px solid black" 
        rowspan=""
        colspan="">
      <p> The extraneous fixed points \(\xi \) </p>

    </td>
    <td  style="border-top-style:solid; border-top-color:black; border-top-width:1px; text-align:center; border-right:1px solid black" 
        rowspan=""
        colspan="">
      <p> Numbers of \(\xi \) </p>

    </td>
  </tr>
  <tr>
    <td  style="border-top-style:solid; border-top-color:black; border-top-width:1px; text-align:center; border-right:1px solid black; border-left:1px solid black" 
        rowspan=""
        colspan="">&nbsp;</td>
    <td  style="border-top-style:solid; border-top-color:black; border-top-width:1px; text-align:left; border-right:1px solid black" 
        rowspan=""
        colspan="">
      <p>\( -0.555220397255420\pm 1.15928646739103i \)</p>

    </td>
    <td  style="border-top-style:solid; border-top-color:black; border-top-width:1px; text-align:center; border-right:1px solid black" 
        rowspan=""
        colspan="">&nbsp;</td>
  </tr>
  <tr>
    <td  style="text-align:center; border-right:1px solid black; border-left:1px solid black" 
        rowspan=""
        colspan="">&nbsp;</td>
    <td  style="text-align:left; border-right:1px solid black" 
        rowspan=""
        colspan="">
      <p>\( -0.460115602837211\pm 0.456390703516719i \)</p>

    </td>
    <td  style="text-align:center; border-right:1px solid black" 
        rowspan=""
        colspan="">&nbsp;</td>
  </tr>
  <tr>
    <td  style="text-align:center; border-right:1px solid black; border-left:1px solid black" 
        rowspan=""
        colspan="">
      <p>Z8 </p>

    </td>
    <td  style="text-align:left; border-right:1px solid black" 
        rowspan=""
        colspan="">
      <p>\( -0.450000501793328\pm 0.129063966758804i \)</p>

    </td>
    <td  style="text-align:center; border-right:1px solid black" 
        rowspan=""
        colspan="">
      <p> \(10\) </p>

    </td>
  </tr>
  <tr>
    <td  style="text-align:center; border-right:1px solid black; border-left:1px solid black" 
        rowspan=""
        colspan="">&nbsp;</td>
    <td  style="text-align:left; border-right:1px solid black" 
        rowspan=""
        colspan="">
      <p>\( 1.89303155290658\pm 0.233570409469479i \)</p>

    </td>
    <td  style="text-align:center; border-right:1px solid black" 
        rowspan=""
        colspan="">&nbsp;</td>
  </tr>
  <tr>
    <td  style="text-align:center; border-right:1px solid black; border-left:1px solid black" 
        rowspan=""
        colspan="">&nbsp;</td>
    <td  style="text-align:left; border-right:1px solid black" 
        rowspan=""
        colspan="">
      <p>\( 1.79931236664623,\) \(2.67863086464586 \) </p>

    </td>
    <td  style="text-align:center; border-right:1px solid black" 
        rowspan=""
        colspan="">&nbsp;</td>
  </tr>
  <tr>
    <td  style="border-top-style:solid; border-top-color:black; border-top-width:1px; text-align:center; border-right:1px solid black; border-left:1px solid black" 
        rowspan=""
        colspan="">&nbsp;</td>
    <td  style="border-top-style:solid; border-top-color:black; border-top-width:1px; text-align:left; border-right:1px solid black" 
        rowspan=""
        colspan="">
      <p>\( -0.555220397255420\pm 1.15928646739103i \)</p>

    </td>
    <td  style="border-top-style:solid; border-top-color:black; border-top-width:1px; text-align:center; border-right:1px solid black" 
        rowspan=""
        colspan="">&nbsp;</td>
  </tr>
  <tr>
    <td  style="text-align:center; border-right:1px solid black; border-left:1px solid black" 
        rowspan=""
        colspan="">&nbsp;</td>
    <td  style="text-align:left; border-right:1px solid black" 
        rowspan=""
        colspan="">
      <p>\( -0.460115602837211\pm 0.456390703516719i \)</p>

    </td>
    <td  style="text-align:center; border-right:1px solid black" 
        rowspan=""
        colspan="">&nbsp;</td>
  </tr>
  <tr>
    <td  style="text-align:center; border-right:1px solid black; border-left:1px solid black" 
        rowspan=""
        colspan="">
      <p>KS8 </p>

    </td>
    <td  style="text-align:left; border-right:1px solid black" 
        rowspan=""
        colspan="">
      <p>\( -0.450000501793328\pm 0.129063966758804i \)</p>

    </td>
    <td  style="text-align:center; border-right:1px solid black" 
        rowspan=""
        colspan="">
      <p> \(10\) </p>

    </td>
  </tr>
  <tr>
    <td  style="text-align:center; border-right:1px solid black; border-left:1px solid black" 
        rowspan=""
        colspan="">&nbsp;</td>
    <td  style="text-align:left; border-right:1px solid black" 
        rowspan=""
        colspan="">
      <p>\( 1.89303155290658\pm 0.233570409469479i \)</p>

    </td>
    <td  style="text-align:center; border-right:1px solid black" 
        rowspan=""
        colspan="">&nbsp;</td>
  </tr>
  <tr>
    <td  style="text-align:center; border-right:1px solid black; border-left:1px solid black" 
        rowspan=""
        colspan="">&nbsp;</td>
    <td  style="text-align:left; border-right:1px solid black" 
        rowspan=""
        colspan="">
      <p>\( 1.79931236664623,\) \(2.67863086464586 \) </p>

    </td>
    <td  style="text-align:center; border-right:1px solid black" 
        rowspan=""
        colspan="">&nbsp;</td>
  </tr>
  <tr>
    <td  style="border-top-style:solid; border-top-color:black; border-top-width:1px; text-align:center; border-right:1px solid black; border-left:1px solid black" 
        rowspan=""
        colspan="">&nbsp;</td>
    <td  style="border-top-style:solid; border-top-color:black; border-top-width:1px; text-align:left; border-right:1px solid black" 
        rowspan=""
        colspan="">
      <p>\(-0.676558832763406\pm 1.36018262584118i \)</p>

    </td>
    <td  style="border-top-style:solid; border-top-color:black; border-top-width:1px; text-align:center; border-right:1px solid black" 
        rowspan=""
        colspan="">&nbsp;</td>
  </tr>
  <tr>
    <td  style="text-align:center; border-right:1px solid black; border-left:1px solid black" 
        rowspan=""
        colspan="">&nbsp;</td>
    <td  style="text-align:left; border-right:1px solid black" 
        rowspan=""
        colspan="">
      <p>\(-0.624888463964184\pm 0.20890104128772i \)</p>

    </td>
    <td  style="text-align:center; border-right:1px solid black" 
        rowspan=""
        colspan="">&nbsp;</td>
  </tr>
  <tr>
    <td  style="text-align:center; border-right:1px solid black; border-left:1px solid black" 
        rowspan=""
        colspan="">&nbsp;</td>
    <td  style="text-align:left; border-right:1px solid black" 
        rowspan=""
        colspan="">
      <p>\(-0.493766364512498\pm 0.607060501953625i \)</p>

    </td>
    <td  style="text-align:center; border-right:1px solid black" 
        rowspan=""
        colspan="">&nbsp;</td>
  </tr>
  <tr>
    <td  style="text-align:center; border-right:1px solid black; border-left:1px solid black" 
        rowspan=""
        colspan="">&nbsp;</td>
    <td  style="text-align:left; border-right:1px solid black" 
        rowspan=""
        colspan="">
      <p>\(-0.461962845726289\pm 0.221119195986523i \)</p>

    </td>
    <td  style="text-align:center; border-right:1px solid black" 
        rowspan=""
        colspan="">&nbsp;</td>
  </tr>
  <tr>
    <td  style="text-align:center; border-right:1px solid black; border-left:1px solid black" 
        rowspan=""
        colspan="">
      <p>M1 </p>

    </td>
    <td  style="text-align:left; border-right:1px solid black" 
        rowspan=""
        colspan="">
      <p>\(-0.204327487662501\pm 0.86651046669376i \)</p>

    </td>
    <td  style="text-align:center; border-right:1px solid black" 
        rowspan=""
        colspan="">
      <p>16</p>

    </td>
  </tr>
  <tr>
    <td  style="text-align:center; border-right:1px solid black; border-left:1px solid black" 
        rowspan=""
        colspan="">&nbsp;</td>
    <td  style="text-align:left; border-right:1px solid black" 
        rowspan=""
        colspan="">
      <p>\(1.932083323\pm 0.1163156841i \)</p>

    </td>
    <td  style="text-align:center; border-right:1px solid black" 
        rowspan=""
        colspan="">&nbsp;</td>
  </tr>
  <tr>
    <td  style="text-align:center; border-right:1px solid black; border-left:1px solid black" 
        rowspan=""
        colspan="">&nbsp;</td>
    <td  style="text-align:left; border-right:1px solid black" 
        rowspan=""
        colspan="">
      <p>\(2.004864313\pm 0.7365790432i \)</p>

    </td>
    <td  style="text-align:center; border-right:1px solid black" 
        rowspan=""
        colspan="">&nbsp;</td>
  </tr>
  <tr>
    <td  style="text-align:center; border-right:1px solid black; border-left:1px solid black; border-bottom-style:solid; border-bottom-color:black; border-bottom-width:1px" 
        rowspan=""
        colspan="">&nbsp;</td>
    <td  style="text-align:left; border-right:1px solid black; border-bottom-style:solid; border-bottom-color:black; border-bottom-width:1px" 
        rowspan=""
        colspan="">
      <p>\(2.083325978\pm 0.4554281653i \)</p>

    </td>
    <td  style="text-align:center; border-right:1px solid black; border-bottom-style:solid; border-bottom-color:black; border-bottom-width:1px" 
        rowspan=""
        colspan="">&nbsp;</td>
  </tr>
</table> <br /><div class="centered"><small class="footnotesize"><sup>a</sup><i class="it"><small class="tiny">To save space, we do not include other points in <a href="#tab6">table 5</a>.</small></i><br /><figcaption>
  <span class="caption_title">Table</span> 
  <span class="caption_ref">5</span> 
  <span class="caption_text">The extraneous fixed points.</span> 
</figcaption>  </small></div></small></div>
</div>
<p><br />figuresection </p>
<figure id="fig1:images-H">
  <div class="centered"><figure class="subfigure" id="f1:grf-A">
 <img src="img-0001.png" alt="\includegraphics[width=0.25\textwidth ]{M1.png}" style="width:0.25" />

<figcaption>
<span class="subcaption">M1</span>
</figcaption>
</figure>  <figure class="subfigure" id="f1:n16mu2m1-A">
 <img src="img-0002.png" alt="\includegraphics[width=0.25\textwidth ]{(5).png}" style="width:0.25" />

<figcaption>
<span class="subcaption">KS8</span>
</figcaption>
</figure>  <figure class="subfigure" id="f1:n16mu2m2-B">
 <img src="img-0003.png" alt="\includegraphics[width=0.25\textwidth ]{L8.png}" style="width:0.25" />

<figcaption>
<span class="subcaption">L8</span>
</figcaption>
</figure>  <br /><figure class="subfigure" id="f1:grf-B">
 <img src="img-0004.png" alt="\includegraphics[width=0.25\textwidth ]{S8.png}" style="width:0.25" />

<figcaption>
<span class="subcaption">S8</span>
</figcaption>
</figure>  <figure class="subfigure" id="f1:n16mu2m1-C">
 <img src="img-0005.png" alt="\includegraphics[width=0.25\textwidth ]{SS8.png}" style="width:0.25" />

<figcaption>
<span class="subcaption">SS8</span>
</figcaption>
</figure>  <figure class="subfigure" id="f1:n16mu2m2-D">
 <img src="img-0006.png" alt="\includegraphics[width=0.25\textwidth ]{SV8.png}" style="width:0.25" />

<figcaption>
<span class="subcaption">SV8</span>
</figcaption>
</figure> <br /><figure class="subfigure" id="f1:grf-D">
 <img src="img-0007.png" alt="\includegraphics[width=0.25\textwidth ]{T8.png}" style="width:0.25" />

<figcaption>
<span class="subcaption">T8</span>
</figcaption>
</figure>  <figure class="subfigure" id="f1:n16mu2m1-F">
 <img src="img-0008.png" alt="\includegraphics[width=0.25\textwidth ]{[4].png}" style="width:0.25" />

<figcaption>
<span class="subcaption"><span class="cite">
	[
	
	<a href="#3'" >4</a>
	
	]
</span></span>
</figcaption>
</figure>  <figure class="subfigure" id="f1:n16mu2m2-F">
 <img src="img-0009.png" alt="\includegraphics[width=0.25\textwidth ]{(4).png}" style="width:0.25" />

<figcaption>
<span class="subcaption">Z8</span>
</figcaption>
</figure>  <br /><figure class="subfigure" id="f1:grf-E">
 <img src="img-0010.png" alt="\includegraphics[width=0.25\textwidth ]{CH8.png}" style="width:0.25" />

<figcaption>
<span class="subcaption">CH8</span>
</figcaption>
</figure>  <figure class="subfigure" id="f1:n16mu2m1-E">
 <img src="img-0011.png" alt="\includegraphics[width=0.25\textwidth ]{K8.png}" style="width:0.25" />

<figcaption>
<span class="subcaption">K8</span>
</figcaption>
</figure>  <figure class="subfigure" id="f1:n16mu2m2-H">
 <img src="img-0012.png" alt="\includegraphics[width=0.25\textwidth ]{KT8.png}" style="width:0.25" />

<figcaption>
<span class="subcaption">KT8</span>
</figcaption>
</figure> <figcaption>
  <span class="caption_title">Figure</span> 
  <span class="caption_ref">1</span> 
  <span class="caption_text">(color online) Basins of attraction of different derivative–free three–point iterations on \(z^3-1\).</span> 
</figcaption>  </div>

</figure>
<p><br /></p>
<p><small class="footnotesize">  </small></p>
<div class="bibliography">
<h1>Bibliography</h1>
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</a> </p>
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</a> </p>
</dd>
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</dd>
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</dd>
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</a> </p>
</dd>
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</a> </p>
<p><br /></p>
</dd>
  <dt><a name="n16">19</a></dt>
  <dd><p><a href ="https://doi.org/10.1016/j.amc.2018.08.006"> <i class="sc">E. Cătinaş</i>, <i class="it">A survey on the high convergence orders and computational convergence orders of sequences</i>, Appl. Math. Comput., <b class="bf">343</b> (2019), pp.&#160;1–20. <img src="img-0013.png" alt="\includegraphics[scale=0.1]{ext-link.png}" style="width:12.0px; height:10.700000000000001px" />
</a> </p>
</dd>
  <dt><a name="Pot12">20</a></dt>
  <dd><p><i class="sc">F. A. Potra</i>, <i class="it">Nondiscrete Induction and Iterative Processes</i>, Pitman, London, 1984. </p>
</dd>
  <dt><a name="OR:16">21</a></dt>
  <dd><p><i class="sc">J.M. Ortega, W.C. Rheinboldt</i>, <i class="it">Iterative Solutions of Nonlinear Equations in Several Variables</i>, Academic Press, New York, 1970. </p>
</dd>
</dl>


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